Question

我正在试图将一个正在运行的curl命令转换为c＃WebRequest的墙上敲我的头。

我已阅读了不少帖子，我非常确定我的代码是正确的，但它仍然无效。

有人能看到我做错了吗？

这是工作curl命令：

curl -k -u x:reallylongstring -H "Content-Type: application/json"  https://api.somewhere.com/desk/external_api/v1/customers.json

这是我用c＃编写的代码：

WebRequest wrGETURL;
wrGETURL = WebRequest.Create("https://api.somewhere.com/desk/external_api/v1/customers.json");
wrGETURL.Method = "GET";
wrGETURL.ContentType = "application/json"; 
wrGETURL.Credentials = new NetworkCredential("x", "reallylongstring");
Stream objStream = wrGETURL.GetResponse().GetResponseStream();
StreamReader objReader = new StreamReader(objStream);
string responseFromServer = objReader.ReadToEnd();

但是api回应：

The remote server returned an error: (406) Not Acceptable.

非常感谢任何帮助！

由于

Answer 1

根据Nikolaos的指示，我似乎用以下代码解决了这个问题：

public static gta_allCustomersResponse gta_AllCustomers()
    {
        var httpWebRequest = (HttpWebRequest)WebRequest.Create("https://api.somewhere.com/desk/external_api/v1/customers.json");
        httpWebRequest.ContentType = "application/json";
        httpWebRequest.Accept = "*/*";
        httpWebRequest.Method = "GET";
        httpWebRequest.Headers.Add("Authorization", "Basic reallylongstring");

        var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();

        using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
        {
            gta_allCustomersResponse answer =  JsonConvert.DeserializeObject<gta_allCustomersResponse>(streamReader.ReadToEnd());
            return answer;
        }
    }

Answer 2

这是我用来发布json数据的curl命令：

curl http://IP:PORT/my/path/to/endpoint -H 'Content-type:application/json' -d '[{...json data...}]'

这相当于上面使用C＃的curl命令：

var url = "http://IP:PORT/my/path/to/endpoint";
var jsonData = "[{...json data...}]";

using (var client = new WebClient())
{
    client.Headers.Add("content-type", "application/json");
    var response = client.UploadString(url, jsonData);
}

Answer 3

这是我将json数据发布到使用API调用或web服务的解决方案

    public static void PostJsonDataToApi(string jsonData)
    {

        var httpWebRequest = (HttpWebRequest)WebRequest.Create("https://api.somewhere.com/v2/cases");
        httpWebRequest.ReadWriteTimeout = 100000; //this can cause issues which is why we are manually setting this
        httpWebRequest.ContentType = "application/json";
        httpWebRequest.Accept = "*/*";
        httpWebRequest.Method = "POST";
        httpWebRequest.Headers.Add("Authorization", "Basic ThisShouldbeBase64String"); // "Basic 4dfsdfsfs4sf5ssfsdfs=="
        using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
        {
           // we want to remove new line characters otherwise it will return an error
            jsonData= thePostBody.Replace("\n", ""); 
            jsonData= thePostBody.Replace("\r", "");
            streamWriter.Write(jsonData);
            streamWriter.Flush();
            streamWriter.Close();
        }

        try
        {
            HttpWebResponse resp = (HttpWebResponse)httpWebRequest.GetResponse();
            string respStr = new StreamReader(resp.GetResponseStream()).ReadToEnd();
            Console.WriteLine("Response : " + respStr); // if you want see the output
        }
        catch(Exception ex)
        {
         //process exception here   
        }

    }

Answer 4

根据关于406的问题：What is "406-Not Acceptable Response" in HTTP?或许你可以尝试在你的请求中添加接受标题？也许curl会自动添加。

你的curl请求中还有-k告诉它忽略SSL验证，我不确定它是否会影响.NET代码。换句话说，如果没有'-k'，curl是否仍然可以工作？然后，不用担心。否则，您可能需要告诉.NET也忽略SSL验证。

WebRequest等效于CURL命令

4 个答案: