Question

尝试编辑以前保留的邮件实体时出现以下错误：

表单的视图数据应该是标量，数组或\ ArrayAccess的实例，但是类Proxies__CG __ \ Mail \ Bundle \ Entity \ Departement的实例。您可以通过将“data_class”选项设置为“Proxies _CG __ \ Mail \ Bundle \ Entity \ Departement”或添加一个视图转换器来将类Proxies__CG __ \ Mail \ Bundle \ Entity \ Departement的实例转换为标量，数组或\ ArrayAccess的实例。

但有时，另一个出现：

表单的视图数据应该是标量，数组或\ ArrayAccess的实例，但是类Mail \ UserBundle \ Entity \ MailUser的实例。您可以通过将“data_class”选项设置为“Mail \ UserBundle \ Entity \ MailUser”或通过添加视图转换器来将此问题转移到“标记”，“数组”或“实例”的实例，该视图转换器将类Mail \ UserBundle \ Entity \ MailUser的实例转换为ArrayAccess接口。

基本上，我有3个实体参与了这个问题：MailEntity，MailUserEntity和DepartementEntity。

这是我的邮件实体：

<?php

namespace Mail\Bundle\Entity;
use Doctrine\ORM\Mapping as ORM;

/**
 * Mail
 */
class Mail {

/**
 * @var integer
 */
 private $id;

/**
 * @var \Mail\Bundle\Entity\Departement
 */
private $departement;

/**
 * @var \Mail\UserBundle\Entity\MailUser
 */
private $mailUser;

/**
 * @var \Mail\UserBundle\Entity\MailUser
 */
private $modifUser;

// Some more variables & Getters / Setters

/**
 * Get id
 *
 * @return integer 
 */
public function getId() {
    return $this->id;
}

/**
 * Constructor
 */
public function __construct() {
}

/**
 * Set departement
 *
 * @param \Mail\Bundle\Entity\Departement $departement
 * @return Mail
 */
public function setDepartement(
        \Mail\Bundle\Entity\Departement $departement = null) {
    $this->departement = $departement;

    return $this;
}

/**
 * Get departement
 *
 * @return \Mail\Bundle\Entity\Departement 
 */
public function getDepartement() {
    return $this->departement;
}

/**
 * Set mailUser
 *
 * @param \Mail\UserBundle\Entity\MailUser $mailUser
 * @return Mail
 */
public function setMailUser(
        \Mail\UserBundle\Entity\MailUser $mailUser = null) {
    $this->mailUser = $mailUser;

    return $this;
}

/**
 * Get mailUser
 *
 * @return \Mail\UserBundle\Entity\MailUser 
 */
public function getMailUser() {
    return $this->mailUser;
}

/**
 * Set modifUser
 *
 * @param \Mail\UserBundle\Entity\MailUser $modifUser
 * @return Mail
 */
public function setModifUser(
        \Mail\UserBundle\Entity\MailUser $modifUser = null) {
    $this->modifUser = $modifUser;

    return $this;
}

/**
 * Get modifUser
 *
 * @return \Mail\UserBundle\Entity\MailUser 
 */
public function getModifUser() {
    return $this->modifUser;
}
}

和yml版本（我使用的版本），如果首选：

Mail\Bundle\Entity\Mail:
type: entity
table: null
repositoryClass: Mail\Bundle\Repository\MailRepository  
fields:
    id:
        type: integer
        id: true
        generator:
            strategy: AUTO
manyToOne:
    departement:
        targetEntity: Mail\Bundle\Entity\Departement
        joinColumns:
            departement_id:
                referencedColumnName: id
        orphanRemoval: false
    mailUser:
        targetEntity: Mail\UserBundle\Entity\MailUser
        joinColumns:
            mail_user_id:
                referencedColumnName: id
        orphanRemoval: false
    modifUser:
        targetEntity: Mail\UserBundle\Entity\MailUser
        joinColumns:
            modif_user_id:
                referencedColumnName: id
        orphanRemoval: false
lifecycleCallbacks: {  }

这是表格类型：

<?php
namespace Mail\Bundle\Form;

use Doctrine\ORM\EntityRepository;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
use Symfony\Component\Security\Core\SecurityContext;

class MailType extends AbstractType
{
protected $userId;

/**
 * @param FormBuilderInterface $builder
 * @param array $options
 */
public function buildForm(FormBuilderInterface $builder, array $options)
{
    $userId = $this->userId;

    $builder

        // Some other fields ... 
        ->add('departement', 'hidden', array(
                'label' => 'Departement',
                'required' => false,
                'disabled' => true))

        ->add('mailUser', 'entity', array(
                'class' => 'MailUserBundle:MailUser',
                'query_builder' => function(EntityRepository $ermu) {
                    return $ermu->createQueryBuilder('MU')
                    ->orderBy('MU.lastName', 'ASC');
                },
                'multiple' => false,
                'required' => true,
                'label' => 'Sender'))

        ->add('modifUser', 'hidden', array(
                'label' => 'Editor'))
    ;
}

/**
 * @param OptionsResolverInterface $resolver
 */
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'Mail\Bundle\Entity\Mail'
    ));
}

/**
 * @return string
 */
public function getName()
{
    return 'mail_bundle_courriertype';
}

public function __construct($userId)
{
    $this->userId = $userId;
}
}

Answer 1

为什么要在表单中添加部门作为隐藏字段？尝试删除它，因为它不是必需的。您已经在实体中获得了它，并且可以在您的控制器中设置/操作它。你的表格中没有必要（也许你来自sf1.4？）....

Symfony2：无法将持久化对象加载到编辑表单中（表单的视图数据应该是标量，数组或\ ArrayAccess实例）

1 个答案: