我很长时间以来第一次与struct合作，我遇到了多个问题。我只是想系统地解决它们，但这个特别给我带来了困难。当我尝试make该程序时，我得到了这个：
`datime.c:9:23:error: expected ‘;’, ‘,’ or ‘)’ before ‘.’ token bool
isConflict(Class.Time*, Class.Time*){`
和
`datime.c:18:21: error: expected ‘;’, ‘,’ or ‘)’ before ‘.’ token bool
isEarlier(Time.Start*, Time.Start*){`.
我的档案schedule.h：
/*
* file: datime.h
*/
typedef struct
{ int hour;
int min;
} Start;
typedef struct
{ int hour;
int min;
} Stop;
typedef struct
{ struct Start;
struct Stop;
} Time;
typedef struct
{ struct Time;
int Days[7];
} Class;
bool isConflict(struct TimeA*, struct TimeB*);
bool isEarlier(struct TimeA*, struct TimeB*);
我的档案schedule.c：
/*
* file: datime.c
*/
#include <stdio.h>
#include <stdbool.h>
#include "datime.h"
bool isConflict(Class.Time*, Class.Time*){
free(classA);
free(classB);
if ((classA.Start <= classB.Start) && (classA.Stop >= classB.Stop))
return 1;
else
return 0;
}
bool isEarlier(Time.Start*, Time.Start*){
free(classA);
free(classB);
if (classA.Start < classB.Start)
return 1;
else
return 0;
}
另外，driver.c仅用于测试函数和struct：
#include <stdbool.h>
#include "datime.h"
main()
{
void setClass(struct Class)
{ struct Class EE205{
EE205.Time.Start.hour = 8;
EE205.Time.Start.min = 30;
EE205.Time.Stop.hour = 9;
EE205.Time.Stop.min = 20;
// Initializing array to zero
memset(EE205.Days, 0, 7 * sizeof(Days[0]));
EE205.Days[1] = 1;
EE205.Days[3] = 1;
EE205.Days[5] = 1;
};
struct Class EE367{
EE367.Time.Start.hour = 10;
EE367.Time.Start.min = 30;
EE367.Time.Stop.hour = 11;
EE367.Time.Stop.min = 20;
// Initializing array to zero
memset(EE367.Days, 0, 7 * sizeof(Days[0]));
EE367.Days[1] = 1;
EE367.Days[3] = 1;
EE367.Days[5] = 1;
};
struct Class EE315{
EE315.Time.Star.hour = 12;
EE315.Time.Start.min = 30;
EE315.Time.Stop.hour = 13;
EE315.Time.Stop.min = 20;
// Initializing array to zero
memset(EE315.Days, 0, 7 * sizeof(Days[0]));
EE315.Days[1] = 1;
EE315.Days[3] = 1;
EE315.Days[5] = 1;
};
if(isConflict(EE315, EE367))
printf("Scheduling conflict! EE315 and EE367 conflict.");
if(isConflict(EE315, EE205))
printf("Scheduling conflict! EE315 and EE205 conflict.");
if(isConflict(EE205, EE367))
printf("Scheduling conflict! EE205 and EE367 conflict.");
}
有很多错误，但这些错误是我无法通过任何原因传递的两个错误。提前谢谢。
答案 0 :(得分：4)
这不是任何合法的C语法。
bool isConflict(Class.Time*, Class.Time*)
（实际上几乎没有代码是有效的。我建议你开始用更小的例子/程序学习结构和指针）
您必须将其声明为例如
bool isConflict(Class* classA, Class *classB){
身体也很奇怪，我无法弄清楚你打算做什么：
free(classA); <--- free() classA/classB, but 2 lines down you try to access them ?
free(classB);
// if ((classA.Start <= classB.Start) && (classA.Stop >= classB.Stop))
//since classA/classB are pointers you need -> to access their members:
// You also need to compare the members of Time, you can't compare structs
// in C, e.g. to check the hours:
if ((classA->Start.hour <= classB->Start.hour) &&
(classA->Stop.hour >= classB->Stop.hour))
return 1;
else
return 0;
}
你的isEelier功能有同样的问题。
main()
{
//you can't declare a function within another function like this.
//what is the purpose of the setClass function ? There is no code that calls this function
//you also need to give names to your function parameters, if you want a pointer, it'd be
//void setClass(struct Class *my_class)
void setClass(struct Class)
{
您的Time结构错误，您没有向成员提供任何变量名称，它应该是：
typedef struct
{ Start Start;
Stop Stop;
} Time;
（但是，您的struct Start和struct Stop是相同的，不需要为两者创建2个结构定义
结构的初始值设定项错误：
struct Class EE205{
EE205.Time.Start.hour = 8;
EE205.Time.Start.min = 30;
EE205.Time.Stop.hour = 9;
EE205.Time.Stop.min = 20;
};
请注意，您说struct Class，但您没有定义struct Class。你有一个typedef
对于一个结构，typedef只是被称为Class，所以编译器不会知道struct Class，它只知道Class
您可以设置以下成员：
Class EE205;
EE205.Time.Start.hour = 8;
EE205.Time.Start.min = 30;
EE205.Time.Stop.hour = 9;
EE205.Time.Stop.min = 20;
// Initializing array to zero
memset(EE205.Days, 0, 7);
EE205.Days[1] = 1;
EE205.Days[3] = 1;
EE205.Days[5] = 1;
或者初始化它：
Class EE205 = {
{
{8, 30},
{9,20}
},
{0,1,0,1,0,1}
};
答案 1 :(得分：0)
这是完全错误的，你不能使用结构类型作为结构成员。
/* 2 structures type doing the same thing? */
typedef struct
{ int hour;
int min;
} Start;
typedef struct
{ int hour;
int min;
} Stop;
typedef struct
{ struct Start; /* variable name missing */
struct Stop;
} Time;
typedef struct
{ struct Time;
int Days[7];
} Class;
bool isConflict(struct TimeA*, struct TimeB*); /* makes no sense */
bool isEarlier(struct TimeA*, struct TimeB*);
让我们改写它：
/* Replaced Start/Stop with time */
typedef struct
{ int hour;
int min;
} Time;
/*
Added member names.
Removed struct because using typedef for Time
*/
typedef struct
{ Time start;
Time stop;
} TimeSpan;
typedef struct
{ TimeSpan timeSpan;
int Days[7];
} Class;
/*
First type, then variable name for each parameter.
Also removed the invalid struct marker.
*/
bool isConflict(Time * a, Time * b);
bool isEarlier(Time * a, Time * b);
这不能解决实际代码的问题，但现在你应该这样做了 至少让你的类型声明正确。
答案 2 :(得分：0)
您有多处错误。
typedef，因此无需在struct
struct中输入类型即可忘记name 这是您的头文件：
/*
* file: datime.h
*/
typedef struct
{ int hour;
int min;
} Start;
typedef struct
{ int hour;
int min;
} Stop;
typedef struct
{ Start start;
Stop stop;
} Time;
typedef struct
{ Time time;
int days[7];
} Class;
bool isConflict(Time *timeA, Time *timeB);
bool isEarlier(Time *timeA, Time *timeB);
在您的源文件中也存在错误：
struct指针，以便访问您必须使用->而不是. bool使用<stdbool.h>，因此您应该返回true或false free稍后您将访问的内容（或者您将遇到分段错误）这是您的源文件：
/*
* file: datime.c
*/
#include <stdio.h>
#include <stdbool.h>
#include "datime.h"
bool isConflict(Time *timeA, Time *timeB) {
if ((timeA->start <= timeB->start) && (timeA->stop >= timeB->stop))
return true;
else
return false;
}
bool isEarlier(Time *timeA, Time *timeB) {
if (timeA->start < timeB->start)
return true;
else
return false;
}
你的主要还有很多错误。我让你看到其他的回应......