这里
SELECT
COUNT(*)
FROM
tbl_department
RIGHT JOIN tbl_video
ON tbl_video.department_id = tbl_department.department_id
LEFT JOIN tbl_language
ON tbl_language.language_id = tbl_video.video_language
WHERE tbl_video.department_id LIKE '%1%'
我已经尝试了
SELECT
COUNT(*)
FROM
tbl_department
RIGHT JOIN tbl_video
ON tbl_video.department_id = tbl_department.department_id
LEFT JOIN tbl_language
ON tbl_language.language_id = tbl_video.video_language AS numbers
WHERE tbl_video.department_id LIKE '%1%'
但它不起作用。 帮忙。
答案 0 :(得分:2)
用于选择
即
SELECT
COUNT(*) AS numbers
.....
不要在某处使用AS ..在选择
中使用它答案 1 :(得分:2)
SELECT
COUNT(*) as total_records
FROM
tbl_department
RIGHT JOIN tbl_video
ON tbl_video.department_id = tbl_department.department_id
LEFT JOIN tbl_language
ON tbl_language.language_id = tbl_video.video_language
WHERE tbl_video.department_id LIKE '%1%';
这将显示所有选定记录的计数。
答案 2 :(得分:1)
你在找这个吗?
SELECT COUNT(*) AS Numbers FROM ...
^^^^^^^^^^
答案 3 :(得分:0)
使用(*)时它表示所有列,“AS”可用于一列,因此表tbl_department中的列具有一列。
答案 4 :(得分:0)
基本上你也可以为别名提供表名,以便在join子句中使用, 像这样的东西:
SELECT
COUNT(*) as total_records
FROM
tbl_department as td --the word 'as' is not mandatory , you can just directly give it an alias
RIGHT JOIN tbl_video as tv
ON tv.department_id = td.department_id -- using the aliases
LEFT JOIN tbl_language as tl -- using the aliases
ON tl.language_id = tv.video_language -- using the aliases
WHERE tv.department_id LIKE '%1%';
顺便说一句,最佳做法是使用“左连接”
所以你可以安排你加入的桌子的顺序
参见示例:
SELECT
COUNT(*) as total_records
FROM tbl_video as tv
LEFT JOIN tbl_department as td
ON tv.department_id = td.department_id
LEFT JOIN tbl_language as tl
ON tl.language_id = tv.video_language
WHERE tv.department_id LIKE '%1%';