我开始掌握一些编程基础,但我仍然很新,没有经验。我正在编写一个我正在编码的新程序。
我希望有一个程序,其中8位二进制数放在文本框中,按下按钮,并显示二进制数的十进制值。
以下是我尝试的代码:
Public Class Form1
Private Sub btnConvert_Click(sender As Object, e As EventArgs) Handles btnConvert.Click
Dim N As Integer
N = Convert.ToDouble(tbxBin.Text)
N = N Mod 2
N = N \ 2
lblAns.Text = Convert.ToString(N)
End Sub
End Class
可悲的是,当我运行程序时,无论我输入什么二进制代码,我都只得到十进制数。我很困惑,因为我被告知使用Mod类。当我在网上寻找解决问题的方法时,我会看到我以前从未见过的技术和各种编码过程。
显然,对于我的代码,我必须重复我输入的内容,因为用户输入了很多位,但是,我很困惑我是如何去做的。我是否对新变量进行了暗淡处理?
非常感谢任何和所有帮助。谢谢。
答案 0 :(得分:2)
编辑:请参阅下面的其他方式!!我误读了。
二进制到十进制:
Public Function ConvertFromBinary(ByVal input As String) As Integer
Dim ret As Integer = 0
Dim splitInput As Char() = input.ToCharArray
Dim modifier As Integer = 1
For i As Integer = splitInput.Length - 1 To 0 Step -1
Dim thisChar As Integer = Val(splitInput(i))
If thisChar = 1 Then
ret += thisChar * modifier
End If
modifier *= 2
Next
Return ret
End Function
......又回来了:
简单回答?
Convert.ToString(input, 2)
然而,这并不好玩:
Public Function ConvertToBinary(ByVal input As Integer) As String
Dim ret As String = ""
While input > 0
ret &= input Mod 2
input = input \ 2
End While
Return StrReverse(ret)
End Function
答案 1 :(得分:1)
艰难的方式
Private Sub btnConvert_Click(sender As Object, e As EventArgs) Handles btnConvert.Click
Dim pwrOf2 As Integer = 0
Dim ans As Long = 0L
'first check if the user input a number
If Long.TryParse(tbxBin.Text, Nothing) Then
'then look at each char in reverse
For Each n As Char In tbxBin.Text.Reverse
Select Case n
Case Is = "0"c
Case Is = "1"c
ans += 1L << pwrOf2
Case Else
'error - input not in binary, only 1's and 0's
Stop
End Select
pwrOf2 += 1
Next
lblAns.Text = ans.ToString("n0")
Else
'not a number
End If
End Sub
答案 2 :(得分:1)
只是一个建议,首先要做一个像这样的函数:
Public Function Bin_To_Dec(ByVal Bin As String)
Dim dec As Double = Nothing
Dim length As Integer = Len(Bin)
Dim temp As Integer = Nothing
Dim x As Integer = Nothing
For x = 1 To length
temp = Val(Mid(Bin, length, 1))
length = length - 1
If temp <> "0" Then
dec += (2 ^ (x - 1))
End If
Next
Return dec
End Function
然后用它来调用它:
txtZ.Text = Bin_To_Dec(txtX.Text)
答案 3 :(得分:0)
首先转换为整数数组,然后将其转换为二进制,请参阅下面的代码
public static Byte[] SerializeDecimal(Decimal decimalValue)
{
Int32[] arraydDecimalToInt32 = Decimal.GetBits(decimalValue); ;
Byte[] byteData = new byte[sizeof(Int32) * arraydDecimalToInt32.Length];
for (Int32 index2 = 0; index2 < arraydDecimalToInt32.Length; index2++)
{
Array.Copy(BitConverter.GetBytes(arraydDecimalToInt32[index2]), 0, byteData, index2 * sizeof(Int32), sizeof(Int32));
}
return byteData;
}
public static Decimal DeserializeDecimal( Byte[] data)
{
Int32[] parts = new Int32[4];
for (Int32 index = 0; index < 4; index++)
{
parts[index] = BitConverter.ToInt32(data, index*4);
}
bool sign = (parts[3] & 0x80000000) != 0;
byte scale = (byte)((parts[3] >> 16) & 0x7F);
return new Decimal(parts[0], parts[1], parts[2], sign, scale);
//See http://msdn.microsoft.com/en-us/library/system.decimal.getbits(v=vs.110).aspx
}
答案 4 :(得分:-1)
Sub Main()
Dim binarystring As String
Dim bitvalue As Integer
Dim denaryvalue As Integer = 0
Dim bit As String
Dim i As Integer
Console.WriteLine("Enter the binary string")
binarystring = Console.ReadLine
Dim lenstring As Integer = Len(binarystring)
For i = 1 To Len(binarystring)
bit = Mid(binarystring, i, 1)
bitvalue = Int(bit)
denaryvalue = 2 ^ (lenstring - i) * bitvalue + denaryvalue
Next
Console.WriteLine(denaryvalue)
Console.ReadLine()
End Sub