我是PHP的新手，所以请保持温和！
我正在尝试使用错误消息/确认消息构建一个简单的PHP表单验证。当我提交表单时，它应该检查字段是否为空并显示相应的消息。但它一直给我一个错误，我不明白为什么：
解析错误：语法错误，第6行的process.php中的意外T_IF
这是进程php代码。
<form action="process.php" method="post">
First Name: <input type="text" name="fname"><br>
Last Name: <input type="text" name="lname"><br>
E-mail: <input type="text" name="email"><br>
<input type="hidden" name="submitted" value="1">
<input type="submit">
</form>
<?php
//If form was submitted
if ($_POST['submitted']==1) {
$errormsg = ""; //Initialize errors
if ($_POST[fname]){
$fname = $_POST[fname]; //If fname was entered
}
else{
$errormsg = "Please enter first name";
}
if ($_POST[lname]){
$lname = $_POST[lname]; //If lname was entered
}
else{
if ($errormsg){ //If there is already an error, add next error
$errormsg = $errormsg . ", last name";
}
else{
$errormsg = "Please enter last name";
}
}
if ($_POST[email]){
$email = $_POST[email]; //If email was entered
}
else{
if ($errormsg){ //If there is already an error, add next error
$errormsg = $errormsg . " & email";
}else{
$errormsg = "Please enter email";
}
}
}
if ($errormsg){ //If any errors display them
echo "<div class=\"box red\">$errormsg</div>";
}
//If all fields present
if ($fname && $lname && $email){
//Do something
echo "<div class=\"box green\">Form completed!</div>";
}
?>
答案 0 :(得分：2)
您忘记在帖子数组中添加"，这是导致错误$_POST[lname]更改为$_POST['lname'];的原因。将字符串传递给$_POST[];
if ($_POST["fname"]){
$fname = $_POST[fname]; //If fname was entered
}
else{
$errormsg = "Please enter first name";
}
if ($_POST["lname"]){
$lname = $_POST[lname]; //If lname was entered
}
else{
if ($errormsg){ //If there is already an error, add next error
$errormsg = $errormsg . ", last name";
}
else{
$errormsg = "Please enter last name";
}
}
if ($_POST["email"]){
$email = $_POST["email"]; //If email was entered
}
答案 1 :(得分：1)
对于$ _POST变量，使用语法$ _POST ['你的变量名']
我更正了您的代码，如下所示：
<form action="test.php" method="post">
First Name: <input type="text" name="fname"><br>
Last Name: <input type="text" name="lname"><br>
E-mail: <input type="text" name="email"><br>
<input type="hidden" name="submitted" value="1">
<input type="submit">
</form>
<?php
//If form was submitted
if ($_POST['submitted']==1) {
$errormsg = ""; //Initialize errors
if ($_POST['fname']){
$fname = $_POST['fname']; //If fname was entered
}
else{
$errormsg = "Please enter first name";
}
if ($_POST['lname']){
$lname = $_POST['lname']; //If lname was entered
}
else{
if ($errormsg){ //If there is already an error, add next error
$errormsg = $errormsg . ", last name";
}
else{
$errormsg = "Please enter last name";
}
}
if ($_POST['email']){
$email = $_POST['email']; //If email was entered
}
else{
if ($errormsg){ //If there is already an error, add next error
$errormsg = $errormsg . " & email";
}else{
$errormsg = "Please enter email";
}
}
}
if ($errormsg){ //If any errors display them
echo "<div class=\"box red\">$errormsg</div>";
}
//If all fields present
if ($fname && $lname && $email){
//Do something
echo "<div class=\"box green\">Form completed!</div>";
}
?>
答案 2 :(得分：1)
某些$ _POST变量缺少单引号，这可能是导致错误的原因。但是，一般来说，我已经提出了其他代码建议。 我重新构建了您的代码以使其更具可扩展性，并通过以下增强功能实现更好的实践：
if (!empty($_POST)) {}以确保已发布表单。希望这有帮助！
<form action="process.php" method="post">
First Name: <input type="text" name="fname" value="<?php echo isset($_POST['fname']) ? $_POST['fname'] : ''?>"><br>
Last Name: <input type="text" name="lname" value="<?php echo isset($_POST['lname']) ? $_POST['lname'] : ''?>"><br>
E-mail: <input type="text" name="email" value="<?php echo isset($_POST['email']) ? $_POST['email'] : ''?>"><br>
<input type="submit">
</form>
<?php
//If form was submitted
if (!empty($_POST)) {
$errors = array();
if (empty($_POST['fname'])){
$errors[] = 'First name must be entered.';
}
if (empty($_POST['lname'])){
$errors[] = 'Last name must be entered.';
}
if (empty($_POST['email'])){
$errors[] = 'Email address must be entered.';
}
if ($errors){ //If any errors display them
$error_msg = implode('<br>',$errors);
echo "<div class=\"box red\">$error_msg</div>";
}
//If all fields present
elseif (validate()){
//Do something
echo "<div class=\"box green\">Form completed and validated!</div>";
}
}
function validate() {
/*you can run all your validation methods here, such as check for length, regexp email verification, etc.*/
$validated = false;
if ($_POST['fname'] && $_POST['lname'] && $_POST['email']) {
$validated = true;
}
return $validated;
}
?>
答案 3 :(得分：0)
这里的问题是缺少register globals启用（这在我看来是件好事）并且没有使用正确的字符串封装。
您需要将$_POST[word]的每个存在都更改为$_POST['word']。请注意'。
答案 4 :(得分：0)
正如Ohgodwhy所说，
您需要将$_POST[word]的每个存在都更改为$_POST['word']。请注意'。
为什么使用<input type="hidden" name="submitted" value="1">，这不是一个好习惯。更好用。
if($_SERVER['REQUEST_METHOD'] == "POST")
答案 5 :(得分：-1)
我正在使用简单验证的东西类型。这是我的javascript代码：
var ck_name = /^[A-Za-z0-9 ]{3,50}$/;
var ck_email = /^([\w-]+(?:\.[\w-]+)*)@((?:[\w-]+\.)*\w[\w-]{0,66})\.([a-z]{2,6}(?:\.[a-z]{2})?)$/;
var ck_mob = /^[0-9 ]{8,11}$/;
function validate(form){
var name = form.name.value;
var email = form.email.value;
var mob = form.mob.value;
var errors = [];
if (!ck_name.test(name))
{
errors[errors.length] = "Your valid Name .";
}
if (!ck_email.test(email))
{
errors[errors.length] = "Your must enter a valid email address.";
}
if (!ck_mob.test(mob))
{
errors[errors.length] = "Your valid Mobile Number.";
}
if (errors.length > 0)
{
reportErrors(errors);
return false;
}
return true;
}
function reportErrors(errors)
{
var msg = "Please Enter Valide Data...\n";
for (var i = 0; i<errors.length; i++)
{
var numError = i + 1;
msg += "\n" + numError + ". " + errors[i];
}
alert(msg);
}