Question

我遇到这个问题，php将在json echo中返回重复的行，它在数据库本身工作，只是php在某处弄乱它而且我不确定在哪里。

<?php   
    $con = mysql_connect("host","user","pass");
    if (!$con)
    {
        die('could not connect: ' . mysql_error());
    }
    mysql_select_db("db", $con);

    $sql = "SELECT DISTINCT INFO, ( 6364 * acos( cos( radians(55.952) ) * cos( radians( lat   ) ) * cos( radians( lng ) - radians(-3.187) ) + sin( radians(55.952) ) * sin( radians( lat ) ) ) ) AS distance FROM table HAVING distance <0.5 ORDER BY distance LIMIT 0 , 20";


    $result = mysql_query($sql,$con);
    if (!$result)
    {
        echo "db error\n";
        echo 'MySQL Error : ' . mysql_error();
    }
    while ($row = mysql_fetch_array($result)) 
    {
        $output[]=$row["INFO"]; //added ["INFO"] to protect my location and make the problem easier to see.
        echo (json_encode($output));
    }
?>

它返回：

["This is where I study"]["This is where I study","this is where I live"]["This is where I study","this is where I live","this is where I could swim"]

即。 = [0][0,1][0,1,2]我需要它只返回[0,1,2]进行java操作。

先谢谢你，我是php / mysql的新手，所以欢迎任何评论。

Answer 1

马克是正确的，你需要做这样的事情：

while ($row = mysql_fetch_array($result)) 
{
    $infos[]=$row["INFO"]; //added ["INFO"] to protect my location and make the problem easier to see.        
}

foreach ($infos as $info) {
    echo (json_encode($info));
}

MySQL PHP Query甚至使用DISTINCT返回重复的结果

1 个答案: