Question

DECLARE @TABLE TABLE (ID INT IDENTITY(1,1), FinalDateTime Datetime2(7), 
 ElapsedTime Time(7))

INSERT INTO @TABLE (FinalDateTime, ElapsedTime)
SELECT '2014-01-21 00:00:00.1110010','12:00:00.1100009' 
  -- Expected Output = '2014-01-20 12:00:00.0010001'
UNION ALL
SELECT '2014-01-20 14:00:00.1110010','02:00:00.1100009' 
  -- Expected Output = '2014-01-20 12:00:00.0010001'
UNION ALL
SELECT '2014-01-20 12:02:00.1110010','00:02:00.1100009' 
  -- Expected Output = '2014-01-20 12:00:00.0010001'
UNION ALL
SELECT '2014-01-20 12:00:02.1110010','00:00:02.1100009' 
  -- Expected Output = '2014-01-20 12:00:00.0010001'
UNION ALL
SELECT '2014-01-20 12:00:00.1110010','00:00:00.1100009' 
  -- Expected Output = '2014-01-20 12:00:00.0010001'

SELECT * FROM @TABLE

我想从time(7)中减去Datetime2(7)。我无法弄清楚如何分别减去整个时间而不是HH / MM / SS / MS。

Answer 1

由于粒度，您需要单独执行纳秒计算。因此，减去整秒的经过时间，然后减去纳秒部分。

DECLARE @TABLE TABLE (FinalDateTime Datetime2(7), ElapsedTime Time(7));

INSERT INTO @TABLE (FinalDateTime, ElapsedTime) VALUES
('2014-01-21 00:00:00.1110010','12:00:00.1100009'),
('2014-01-20 14:00:00.1110010','02:00:00.1100009'),
('2014-01-20 12:02:00.1110010','00:02:00.1100009'),
('2014-01-20 12:00:02.1110010','00:00:02.1100009'),
('2014-01-20 12:00:00.1110010','00:00:00.1100009');

;WITH x AS 
(
  SELECT 
    FinalDateTime, 
    ElapsedTime,
    ElapsedSeconds = DATEDIFF(SECOND, '0:00', ElapsedTime),
    AdditionalNanoseconds = DATEPART(NANOSECOND, ElapsedTime)
  FROM @TABLE
)
SELECT 
  FinalDateTime, 
  ElapsedTime, 
  StartTime = DATEADD(NANOSECOND, -AdditionalNanoseconds, 
    DATEADD(SECOND, -ElapsedSeconds, FinalDateTime)
  ) 
FROM x;

你可以更简洁地做到这一点，当然，我只是觉得CTE有助于表达这些步骤。

SELECT 
  FinalDateTime, 
  ElapsedTime, 
  StartTime = DATEADD(NANOSECOND, -(DATEPART(NANOSECOND, ElapsedTime)), 
    DATEADD(SECOND, -(DATEDIFF(SECOND, '0:00', ElapsedTime)), FinalDateTime)
  ) 
FROM @TABLE;

Answer 2

你可以通过以下方式获得支持：

SELECT *, DateAdd( millisecond, DateDiff( millisecond, ElapsedTime, 0 ), FinalDateTime )
  FROM @TABLE

不幸的是，DATEADD和DATEDIFF使用INT来表示间隔。你想要的分辨率存在问题。

计算给定结束时间（datetime2）和持续时间（时间（7））的开始时间

2 个答案: