Question

我创建了一个字典“email”和“password”的字典，并使用这些参数作为我的请求的主体。我得到了我的服务器的响应，我错过了参数电子邮件和密码 - 我很肯定这不是服务器端的问题。这就是我正在形成请求的方式：

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];

NSString *urlString = @"xxxxxx.xxxx.com/userServices/login";
[request setURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];

NSDictionary *params = @{@"email" : email, @"password" : password};
NSData *bodyData = [NSJSONSerialization dataWithJSONObject:params options:NSJSONWritingPrettyPrinted error:nil];
[request setHTTPBody:bodyData];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setCachePolicy:NSURLRequestReloadIgnoringLocalCacheData];
[request setTimeoutInterval:45];
[request setHTTPShouldHandleCookies:NO];

知道为什么服务器不会识别我的参数吗？

Answer 1

创建字典时，我会这样做

NSMutableDictionary *params = [[NSMutableDictionary alloc] init];
[params setValue:[NSString stringWithFormat:@"%@", email] forKey:@"email"];
[params setValue:[NSString stringWithFormat:@"%@", password] forKey:@"password"];

之后我会这样做

NSData *postData = [NSJSONSerialization dataWithJSONObject:params options:0 error:nil];

您可能需要为您的请求提供内容长度

[request setValue:[NSString stringWithFormat:@"%i",postData.length] forHTTPHeaderField:@"Content-Length"];

Answer 2

NSString *post =[[NSString alloc] initWithFormat:@"email=%@&password=%@",[txtUserEmail text],[txtUserPassword text]];
           // what ever in you case e.g [txtuseremail text] replaced by email

            NSURL *url=[NSURL URLWithString:@"http://localhost/abc.php"];

            NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

            NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];


            NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];

            [request setURL:url];
            [request setHTTPMethod:@"POST"];
            [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
        [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
        [request setHTTPBody:postData];

尝试这可能会对你有所帮助

Answer 3

试试这个会对你有用：

NSDictionary * requestDict = [NSDictionary dictionaryWithObjectsAndKeys：@“email”，@“YourEmail”，@“password”，@“YourPassword”，nil];

NSMutableURLRequest * request =[[ NSMutableURLRequest alloc]initWithURL:[NSURL URLWithString:BASE_URL]];

NSData * postData =[ NSJSONSerialization dataWithJSONObject:requestDict options:0 error:nil];

[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];


[NSURLConnection
 sendAsynchronousRequest:request
 queue:[[NSOperationQueue alloc] init]
 completionHandler:^(NSURLResponse *response,
                     NSData *data,
                     NSError *error)
 {

     if ([data length] >0 && error == nil)
     {

         NSDictionary * dictServerResponse =[ NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:nil];

         NSLog(@"data %@",dictServerResponse);
         // DO YOUR WORK HERE

     }
     else if ([data length] == 0 && error == nil)
     {
         NSLog(@"Nothing was downloaded.");
     }
     else if (error != nil){
         NSLog(@"Error = %@", error);
     }

 }];

创建POST请求ios的问题

3 个答案: