Question

我需要在document.write中返回showtime函数来显示时间请帮助我

链接：JS Bin

var timerID = null;
var timerRunning = false;
function showtime()
{
    var now = new Date();
    var hours = now.getHours();
    var tm = " AM";

    if (hours == 12) { tm = " PM"; }

    if (hours < 12) { tm = " AM"; }

    if (hours > 12) { hours = hours - 12; tm = " PM"; }

    if (hours == 0) { tm = " AM"; hours = 12; }

    var minutes = now.getMinutes();
    var seconds = now.getSeconds();
    var timeValue = "" + hours;
    timeValue  += ((minutes < 10) ? ":0" : ":") + minutes;
    timeValue  += ((seconds < 10) ? ":0" : ":") + seconds;
    LocalTimer.innerHTML = timeValue + tm;
    timerID = setTimeout("showtime()",1000);
    timerRunning = true;
}

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Answer 1

我尝试修复代码问题并对代码进行了一些更改。我希望这符合您的要求。

var timerID = null;
var timerRunning = false;
var LocalTimer = document.getElementById("localTimer");
function showtime()
{
    var now = new Date();
    var hours = now.getHours();
    var tm = " AM";

    if (hours == 12) { tm = " PM"; }

    if (hours < 12) { tm = " AM"; }

    if (hours > 12) { hours = hours - 12; tm = " PM"; }

    if (hours === 0) { tm = " AM"; hours = 12; }

    var minutes = now.getMinutes();
    var seconds = now.getSeconds();
    var timeValue = "" + hours;
    timeValue  += ((minutes < 10) ? ":0" : ":") + minutes;
    timeValue  += ((seconds < 10) ? ":0" : ":") + seconds;
    LocalTimer.innerHTML = timeValue + tm;
  timerID = setTimeout(function(){showtime();},1000);
    timerRunning = true;
}

showtime();

请按此link进行更新演示。

document.write中的return函数

1 个答案: