Question

我经常遇到以下情况：我有很长的多行字符串，其中必须注入属性 - 例如像模板一样的东西。但我不想在我的项目中包含一个完整的模板引擎（如速度或自由标记）。

如何以简单的方式完成：

String title = "Princess";
String name  = "Luna";
String community = "Stackoverflow";

String text =
   "Dear " + title + " " + name + "!\n" +  
   "This is a question to " + community + "-Community\n" + 
   "for simple approach how to code with Java multiline Strings?\n" + 
   "Like this one.\n" + 
   "But it must be simple approach without using of Template-Engine-Frameworks!\n" + 
   "\n" + 
   "Thx for ...";

Answer 1

你可以创建自己的小＆amp;只需几行代码的模板引擎：

public static void main(String[] args) throws IOException {

    String title = "Princes";
    String name  = "Luna";
    String community = "Stackoverflow";

    InputStream stream = DemoMailCreater.class.getResourceAsStream("demo.mail");


    byte[] buffer = new byte[stream.available()];
    stream.read(buffer);

    String text = new String(buffer);

    text = text.replaceAll("§TITLE§", title);
    text = text.replaceAll("§NAME§", name);
    text = text.replaceAll("§COMMUNITY§", community);

    System.out.println(text);

}

和小文本文件，例如在同一文件夹（包）demo.mail：

Dear §TITLE§ §NAME§!
This is a question to §COMMUNITY§-Community
for simple approach how to code with Java multiline Strings? 
Like this one.
But it must be simple approach without using of Template-Engine-Frameworks!

Thx for ...

Answer 2

这样做的一个基本方法是使用String.format(...)

示例：

String title = "Princess";
String name  = "Celestia";
String community = "Stackoverflow";

String text = String.format(
    "Dear %s %s!%n" +  
    "This is a question to %s-Community%n" + 
    "for simple approach how to code with Java multiline Strings?%n" + 
    "Like this one.%n" + 
    "But it must be simple approach without using of Template-Engine-Frameworks!%n" + 
    "%n" + 
    "Thx for ...", title, name, community);

More info

Answer 3

您可以使用Java Resources来实现HERE 或者，您可以使用HERE

等不同方法保留当前使用的方法

Answer 4

您可以使用String#format()：

String title = "Princess";
String name  = "Luna";
String community = "Stackoverflow";
String text = String.format("Dear %s %s!\n" +  
            "This is a question to %s-Community\n" + 
            "for simple approach how to code with Java multiline Strings?\n" + 
            "Like this one.\n" + 
            "But it must be simple approach without using of Template-Engine-Frameworks!\n" + 
            "\n" +
            "Thx for ...", title, name, community);

Answer 5

Java没有内置的模板支持。您的选择是：

使用现有的模板框架/引擎，
构建您自己的模板框架/引擎（或类似的），或
写了很多“字符串抨击”代码......就像你的问题一样。

您可以使用String.format(...)，MessageFormat等类似地更简洁地编写上述代码，但它们不会让您走得太远...除非您的模板非常简单。

相比之下，有些语言内置支持字符串插值，“此处”文档或简洁的结构构建语法，可以适应模板。

Answer 6

您可以使用java.text.MessageFormat：

String[] args = {"Princess, "Luna", "Stackoverflow"};

String text = MessageFormat.format("Bla bla, {1}, and {2} and {3}", args);

在java代码中模板化多行字符串的简单方法

6 个答案: