Question

我尝试在Java中使用File and Scanner打开CSV文件，但我无法使用Scanner打开它。以下是代码，任何想法？相关代码位于parseFile函数

中

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;


    public class CIS350HW1 {

        /**
         * @param args
         */
        public static void main(String[] args) {
            boolean quit = false;
            int year = 0;
            while(quit == false){
                printMenu();
                Scanner sc = new Scanner(System.in);
                String str = sc.next().toUpperCase();
                System.out.println(str);
                if (str.equals("Q")) {
                    System.out.println("Good bye");
                    quit = true;
                }
                else if (str.equals("3")) {
                    parseFile(args[0], Integer.parseInt(str), year);
                }
                else if (str.equals("2") || str.equals("1")) {
                    System.out.println("Please enter the year: "); //remember might not be println
                        try { 
                        year = Integer.parseInt(sc.next());
                    } catch(NumberFormatException e) {
                        System.out.print("Invalid formatted input. ");
                    }
                    if (year < 1920 || year > 2010){
                        System.out.println("Not a valid year.");
                        System.out.println();
                    }
                    parseFile(args[0], Integer.parseInt(str), year);
                }
                else {
                    System.out.println("That is not a valid selection.");
                }
            }
        }

        /**
         * prints the menu options to the consul.
         */
        public static void printMenu() {
            System.out.println("Welcome to the Oscars database!");
            System.out.println();
            System.out.println("Please make your selection:");
            System.out.println("1: Search for best picture award winner by year");
            System.out.println("2: Search for best picture award nominees by year");
            System.out.println("3: Search for actor/actress nominations by name");
            System.out.println("Q: Quit");
        }

        public static void parseFile(String args, int n, int year) {
            File file = new File(args);
            Scanner input = null;
            try {
                input = new Scanner(file);
            } catch (FileNotFoundException e) {
                System.out.println("Could not open the file for some reason.");
            }


            while(input.hasNext()) {
                String nextLine = input.nextLine();
                String token[] =  nextLine.split(",");
                if (n == 1) {
                    String tempYear[] = token[0].split(" ");
                    if (Integer.parseInt(tempYear[0]) == year 
                            && token[1].equals("Best Picture") 
                            && token[3].equals("YES")) {
                        System.out.println(token[2]);
                    }
                }
            }

            input.close();
        }

    }

请注意，代码还没有做任何事情，试图弄清楚为什么try / catch永远不会起作用。谢谢！

Answer 1

如果您使用命令行来运行程序（java CIS350HW1 file.csv），那么该文件必须位于同一文件夹中。

但是如果您从IDE（Eclipse或其他）运行程序，那么您的文件必须位于项目的类路径中。

使用Java中的Scanner打开CSV文件

1 个答案: