Question

问题是编写一个程序，要求用户输入5个不同的学生和他们的标记。如果用户试图两次输入学生，程序应该检测到这个并要求他们输入一个唯一的学生姓名（和他们的标记）。

我的节目是..

dictionary = {}

count = 0

while count < 5:
   name = raw_input("Enter your name: ")
   mark = input("Enter your mark out of 100: ")
   if name not in dictionary:
       dictionary[name] = mark
       count = count + 1
   else:
       name = raw_input("Enter a unique name: ")
       mark = input("Enter the mark out of 100: ")
       if name not in dictionary:
          dictionary[name] = mark
          count = count + 1

print dictionary

我的问题是如何循环else：代码如果用户一直输入相同的名称并标记？

Answer 1

dictionary = {}
count = 0
while count < 5:
   name = raw_input("Enter your name: ")
   name = name.strip().lower() # store name in lower case, e.g. aamir and Aamir consider duplicate
   if not dictionary.get(name):
       mark = input("Enter your mark out of 100: ")
       dictionary[name] = mark
       count += 1
   else:
       print "please enter unique name"

print dictionary

以小写字母存储名称，以便aamir和Aamir都应视为重复
应在步骤Enter your mark之前执行重复检查，以便为最终用户保存一个步骤

Answer 2

你混合input和raw_input，这是一件坏事。通常你在Python 2中使用raw_input，在Python 3中使用input。解决问题的快捷方法是：

dictionary = {}

count = 0

while count < 5:
   name = raw_input("Enter your name: ")
   mark = raw_input("Enter your mark out of 100: ")
   if name not in dictionary:
       dictionary[name] = mark
       count = count + 1
   else:
       print("You already used that name, enter an unique name.")

print dictionary

Answer 3

我认为你只需要这样做：

dictionary = {}

count = 0

while count < 5:
      name = raw_input("Enter your name: ")
      mark = input("Enter your mark out of 100: ")
      if name not in dictionary:
          dictionary[name] = mark
          count = count + 1

 print dictionary

Python：要求用户输入5个不同的标记

3 个答案: