Question

我试图将ascii字符转换为二进制。我正在用txt文件读取字符串。

    ; emu8086 version 4.00-Beta-12 or better is required! 
; put file named "input.txt" to c:\emu8086\vdrive\c\ 
; (it's possible to copy "ReadMe.txt" and rename it or use any other 
;file that contains ASCII chars). 

org 100h ; .com memory layout  


mov dx, offset file ; address of file to dx 
mov al,0 ; open file (read-only) 
mov ah,3dh 
int 21h ; call the interupt 
jc terminate ; if error occurs, terminate program 
mov bx,ax ; put handler to file in bx 

mov cx,1 ; read one character at a time    

print: 
lea dx, BUF 
mov ah,3fh ; read from the opened file (its handler in bx) 
int 21h 
CMP AX, 0 ; how many bytes transfered? 
JZ terminate ; end program if end of file is reached (no bytes 
;left). 
mov al, BUF ; char is in BUF, send to ax for printing (char is 
;in al) 
mov ah,0eh ; print character (teletype). 
int 10h 
jmp print ; repeat if not end of file. 


terminate: 
mov ah, 0 ; wait for any key... 
int 16h 
ret 

file db "input.txt", 0 
BUF db ? 


END

所以，我想打印到屏幕的第一个256字节。

总结一下，输入：任何文件，输出如下：文件名：input.txt

00: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
10: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
20: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
30: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
40: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
50: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
60: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
70: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
80: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
90: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00

编辑：

我改变了这个明智的代码

org 100h ; .com memory layout 


table DB '0123456789ABCDEF'


mov dx, offset file ; address of file to dx 
mov al,0 ; open file (read-only) 
mov ah,3dh 
int 21h ; call the interupt 
jc terminate ; if error occurs, terminate program 
mov bx,ax ; put handler to file in bx 

mov cx,1 ; read one character at a time 


print: 
lea dx, BUF 
mov ah,3fh ; read from the opened file (its handler in bx) 
int 21h 
CMP AX, 0 ; how many bytes transfered? 
;JZ terminate ; end program if end of file is reached (no bytes 
;left). 
mov al, BUF ; char is in BUF, send to ax for printing (char is 
;in al)


  ; hex i ekrana bastirma kismi, fakat bu kodlardan sonra
  ; buf degismiyor..  ancak sadece ekrana yazdirirsak buf degisiyor

MOV DL, AL

LEA BX, table ; load data table.

MOV AL, DL
SHR AL, 4 ; leave high part only.
XLAT ; get hex digit. 
MOV AH, 0Eh ; teletype sub-function.
INT 10h


MOV AL, DL
AND AL, 0Fh ; leave low part only.
XLAT ; get hex digit. 
mov ah,0eh ; print character (teletype). 
int 10h 
jmp print ; repeat if not end of file.  




;mov ah,0eh ; print character (teletype). 
;int 10h 
;jmp print ; repeat if not end of file. 


terminate: 
mov ah, 0 ; wait for any key... 
int 16h 
ret 





file db "input.txt", 0 
BUF db ? 


END

但是在这个时候，BUF var不会随着更新的变化而变化。

Answer 1

谷歌稍微透露了这一页：

http://www.dailyfreecode.com/code/convert-hexadecimal-number-binary-1746.aspx

您一定会了解如何将其移植到您想要的平台。

如何在emu8086中将ascii字符转换为二进制

1 个答案: