Question

当我点击提交按钮时，我在调用php函数时遇到问题：

<?php
if (isset($_GET['username']) === true and empty($_GET['username']) === false) {
$username       = $_GET['username'];

if(user_exists($username) === true) {
$profile_user_id        = user_id_from_username($username, 'username');
$my_id                  = $_SESSION['user_id'];
$profile_data           = user_data($profile_user_id, 'username', 'first_name', 'last_name', 'email', 'profile');
?>

    <h1><?php echo $profile_data['first_name']; ?>'s Profile</h1>
    <?php
    if($profile_user_id != $my_id) {
        $check_friend_query = mysql_query("SELECT id FROM friends WHERE (user_one='$my_id' AND user_two='$profile_user_id') OR (user_one='$profile_user_id' AND user_two='$my_id')");
        if(mysql_num_rows($check_friend_query) > 0) {
            echo '<a href="">Already Friends </a>- <a href="">Unfriend '. $profile_data['username'] .'</a>';
        } else {
            $from_query = mysql_query("SELECT id FROM friend_request WHERE `from` = '$profile_user_id' AND `to` = '$my_id'");
            $to_query   = mysql_query("SELECT id FROM friend_request WHERE `from` = '$my_id' AND `to` = '$profile_user_id'");
            if(mysql_num_rows($from_query) == 1) {
                 echo '<a href="#">Ignore</a> or <a href="">Accept</a>';
            } elseif(mysql_num_rows($to_query) == 1){
                 echo '<a href="#">Cancel Request</a>';
            } else {
                 if(isset($_GET['submit'])) {
                    friend_request();
                    header('Location: '.$profile_user_id);
                    exit();
                 }
                    ?>
                        <form action="">
                            <input type="submit" name="submit" value="Send friend request!">
                        </form>
                    <?php
            }
        }
    }
    ?>

最后一个isser（$ GET ['submit']和函数调用form.What错误我找不到解决方案，它只是刷新页面但是doenst发送mysql_query。功能我打电话是这样的：

function friend_request() {
if (isset($_GET['username']) === true and empty($_GET['username']) === false) {
$username       = $_GET['username'];

    if(user_exists($username) === true) {
    $profile_user_id        = user_id_from_username($username, 'username');
    $my_id                  = $_SESSION['user_id'];
    $profile_data           = user_data($profile_user_id, 'username', 'first_name', 'last_name', 'email', 'profile');

mysql_query("INSERT INTO friend_request VALUES('', '$my_id', '$profile_user_id')");
}}}

请帮助我，我是php的新手，这让我很烦恼，自从昨天晚上试图解决它以来我一直坚持这个。我真的没有看到问题是什么。我怎么改变我的代码？一切都很完美期待friend_request（）函数的一部分。

Answer 1

表单中的

username输入缺失，基于username允许加入块if (isset($_GET['username']) === true and empty($_GET['username']) === false) {

的值

    <form action="">
         <input type="text" name="username" value="your value">
        <input type="submit" name="submit" value="Send friend request!">
    </form>

PHP无法调用函数

1 个答案: