计算Python中标点符号之间的单词数

Question

我想使用Python来计算文本输入块中某些标点符号之间出现的单词数。例如，对此处所写的所有内容的此类分析可能表示为：

[23,2,14]

...因为除了句末之外没有标点符号的第一个句子有23个单词，接下来的“例如”短语有两个，其余的以冒号结尾有14个。

这可能不会太难，但（与“不要重新发明轮子”的哲学相似，特别是Pythonic）是否有任何特别适合这项任务的东西？

Answer 1

punctuation_i_care_about="?.!"
split_by_punc =  re.split("[%s]"%punctuation_i_care_about, some_big_block_of_text)
words_by_puct = [len(x.split()) for x in split_by_punc]

Answer 2

Joran打败了我，但我会加入我的方法：

from string import punctuation
import re

s = 'I want to use Python to count the numbers of words that occur between certain punctuation characters in a block of text input. For example, such an analysis of everything written up to this point might be represented as'

gen = (x.split() for x in re.split('[' + punctuation + ']',s))

list(map(len,gen))
Out[32]: [23, 2, 14]

（我喜欢map）