Django在视图和模板中建立模型关系

时间:2014-01-18 15:51:07

标签: django django-templates django-views

我正在研究多用户rss阅读器。我想将帖子的显示仅限于那些未读的帖子。我已经设法在我的单个“提要”视图中执行此操作,如下所示,但我无法弄清楚如何在多个提要也称为“类别”视图中执行相同操作。

我一直在尝试像https://docs.djangoproject.com/en/1.5/topics/db/queries/#spanning-multi-valued-relationships这样的东西,但它对我不起作用

我应该更改“类别”视图代码或模板代码吗?如果是这样你会怎么做呢?

谢谢! -S

模型

class UserCategory(models.Model):
    name = models.CharField(unique=False, max_length=64)
    user = models.ForeignKey(User)
    slug = AutoSlugField(populate_from='name', always_update='True', unique_with='user')

class Feed(models.Model):
    feed_url = models.URLField(unique=True)
    default_title = models.CharField(max_length=64, blank=True)
    link = models.URLField(blank=True)

class UserFeed(models.Model):
    feed = models.ForeignKey(Feed)
    title = models.CharField(max_length=64)
    category = models.ForeignKey(UserCategory)
    user = models.ForeignKey(User)
    slug = AutoSlugField(populate_from='title', always_update='True', unique_with='user')

class Post(models.Model):
    feed = models.ForeignKey(Feed)
    title = models.CharField(max_length=256)
    content = models.TextField()
    link = models.URLField(max_length=512)

class ReadPost(models.Model):
    user = models.ForeignKey(User)
    post = models.ForeignKey(Post)

视图

def feed(request, user_feed_slug):
    user_feed = get_object_or_404(UserFeed.objects.filter(slug=user_feed_slug, user=request.user))
    read_post = ReadPost.objects.filter(user=request.user).values_list('post')
    posts = Post.objects.select_related().filter(feed=user_feed.feed).exclude(id__in=read_post)

def category(request, user_category_slug):
    user_category = get_object_or_404(UserCategory.objects.filter(slug=user_category_slug, user=request.user)) 

模板

feed
    {% for post in posts %}
        {{ post.title }}                    
    {% endfor %}

category
{% for feed in user_category.userfeed_set.all %}
    {{ feed.title }}
    {% for post in feed.feed.post_set.all %}
        {{ post.title }}
        {{ post.content }}
    {% endfor %}
{% endfor %}

2 个答案:

答案 0 :(得分:1)

你可以写custom template filter,即:

@register.filter
def unread(posts, read_posts):
    return posts.exclude(id__in=read_posts)

(在您必须将read_post传递给类别模板上下文之前)。

答案 1 :(得分:0)

试试这个查询集:

def category(request, user_category_slug):
    user_category = get_object_or_404(UserCategory, slug=user_category_slug,
                                           user=request.user))

    feeds = UserFeed.objects.filter(category__slug=user_category_slug, user=request.user)\
                .prefetch_related('feed__post_set')

然后在你的模板中:

{% for feed in feeds %}
    {{ feed.title }}
    {% for post in feed.feed.post_set.all %}
        {{ post.title }}
        {{ post.content }}
    {% endfor %}
{% endfor %}