Question

我正在尝试将字段“ SID ”值插入 tbl1 ，但要获取 SID 它必须引用名字和姓氏到另一个表（ tbl2 ）以获取 SID ，然后我使用了以下SQL语句和后续代码。

    Dim sqlquery As String = "INSERT INTO tblPayments (StudentID,Payment,PaymentDate) VALUES (SELECT StudentID FROM tblStudents WHERE Forename = @Forename AND Surname = @Surname , Payment = @SPaid, PaymentDate = @todaysdate)"

    Dim sqlcommand As New OleDbCommand
    With sqlcommand

        .CommandText = sqlquery

        .Parameters.AddWithValue("@SPaid", Paidtxt.Text)
        .Parameters.AddWithValue("@todaysdate", Today.Date)
        .Parameters.AddWithValue("@Forename", Forenametxt.Text)
        .Parameters.AddWithValue("@Surname", Surnametxt.Text)

        .Connection = conn

        .ExecuteNonQuery()
    End With
    MsgBox("query executed, closing connection")
    conn.Close()

然而，SQLQuery给出了错误：

“System.Data.OleDb.OleDbException”类型的未处理异常发生在System.Data.dll中附加信息：查询表达式中的语法错误'SELECT StudentID FROM tblStudents WHERE Forename = @Forename AND Surname = @Surname”。

但是我看不出指定为错误的声明部分有什么问题，有人可以告诉我它的错误吗？

Answer 1

我认为错误非常明显。 insert . . . select的语法不使用values关键字：

INSERT INTO tblPayments(StudentID, Payment, PaymentDate) 
    SELECT StudentID,  @SPaid, @todaysdate
    FROM tblStudents
    WHERE Forename = @Forename AND Surname = @Surname;

INSERT INTO ... SELECT语句（Access SQL）上的语法错误

1 个答案: