我正在尝试使用MySQL
中的SQLAlchemy
将条目提交到Python
数据库。下面的函数旨在允许我提交一批条目,即使其中一个或两个包含数据库不接受的错误。但是,当它到达一个它无法提交的条目时它不会跳过它并转到下一个条目,它会尝试一遍又一遍地提交相同的条目,为该条目获取相同的错误消息一千次。为什么我的函数中的trycatch不起作用?
def commitentry(database, enginetext, verbose = False):
"""
Takes a database object and text string that defines the SQL
engine and adds all entries in the database list to the SQL
database.
"""
engine = create_engine(enginetext)
Session = sessionmaker()
Session.configure(bind=engine)
session = Session()
counter = 0
for entry in database:
try:
session.add(entry)
session.commit()
except Exception, e:
print("Commit Error")
if verbose:
print(e)
finally:
counter += 1
if verbose:
print(counter, counter/float(len(database)))
if verbose:
print("Entries saved!")
session.close()
答案 0 :(得分:1)
当提交失败时,它不会像成功提交那样从内存中删除对象。因此,当下一个对象被添加到会话时并不是唯一的,刚刚失败的对象仍然存在。将session.rollback()
添加到except块将删除无法从会话保存到数据库的对象,从而允许保存下一个对象。
def commitentry(database, enginetext, verbose = False):
"""
Takes a database object and text string that defines the SQL
engine and adds all entries in the database list to the SQL
database.
"""
engine = create_engine(enginetext)
Session = sessionmaker()
Session.configure(bind=engine)
session = Session()
counter = 0
for entry in database:
try:
session.add(entry)
session.commit()
except Exception, e:
print("Commit Error")
session.rollback()
if verbose:
print(e)
finally:
counter += 1
if verbose:
print(counter, counter/float(len(database)))
if verbose:
print("Entries saved!")
session.close()