Question

这里是我的.cshtml代码：

@model WebComposite.Models.MyModel
@using (Html.BeginForm())
{
      @Html.TextBoxFor(m => m.id)
      @Html.TextBoxFor(m => m.name)
}
@Scripts.Render("~/Scripts/MyScript.js")

这里是MyScript.js中的代码：

$('form').submit(function (e)
{
    e.preventDefault();
    //normal Ajax (my own custom version as i'm sure every one has one of these:)
    SimpleAjax("MyAction", function () { alert("Done"); });
});

Controller代码：

[HttpPost]
public ActionResult MyAction(MyModel model)
{
     //Problem here is model.id and model.name are empty
}

任何想法？提前谢谢

Answer 1

快速浏览后，我猜解决方案非常简单（谢谢jquery !!）：只需序列化表单中的所有内容，然后通过ajax调用将其发送回控制器：

$("form").serializeArray();

这是我自己的Ajax调用的完整实现有3个函数（你将调用SimplAjaxPost（url，funcDelegate），它将为你完成剩下的工作

function Ajax(url, dataObj, getOrPost, theContext, theContentType, theDataType, successFuncName, failedFuncName, alwaysFuncName)
{
    //GET or POST:
    if (getOrPost == null) { getOrPost = 'POST'; }
    //Header (what we're sending to the server): http://stackoverflow.com/questions/2722750/ajax-datatype
    if (theContentType == null) { theContentType = 'application/x-www-form-urlencoded; charset=UTF-8'; }
    //response (what we're expeting in return):http://stackoverflow.com/questions/2722750/ajax-datatype
    if (theDataType == null) { theDataType = ""; }
    //exposing "this" to whatever:  http://stackoverflow.com/questions/5097191/ajax-context-option
    if (theContext == null) { theContext = document.body; }

    var theURL = NoCache(url);
    $.ajax(
    {
        url:            theURL,
        data:           dataObj,
        type:           getOrPost,
        contentType:    theContentType,
        dataType:       theDataType,
        context:        theContext,
        async:          false,
        success:        successFuncName,
        fail:           failedFuncName,
        always:         alwaysFuncName,
        complete:       AjaxScripts
    });
}

function SimpleAjax(url, successFunctionName)
{
    var dataObj = null;
    Ajax(url, dataObj, null, null, null, null, successFunctionName, null, null)
}

function SimpleAjaxPost(url, successFunctionName)
{
    var dataObj = null;
    if ($("form").length == 1)
    {
        dataObj = $("form").serializeArray();
    }
    Ajax(url, dataObj, null, null, null, null, successFunctionName, null, null)
}

function NoCache(url)
{
    var t = new Date();
    var qps = "?";
    if (url.indexOf("?") > 0)
    {
        qps = "&";
    }
    return url + qps + t.getYear() + t.getMonth() + t.getDay() + t.getHours() + t.getMinutes() + t.getSeconds() + t.getMilliseconds();
}

在执行Ajax时将模型传递回Server

1 个答案: