Question

我有问题。我希望我的程序问我插入一个单词，这个单词的字母必须包含在一个数组中。

目前，我想如果字母包含在数组中，打印（“字母是正确的”），否则打印（“字母不正确”）。

但总是回来（“这封信不正确”），为什么？

请帮助我！

public class Utils {

Scanner ent = new Scanner(System.in);
String insertedLetter = "";
String letters[] = {"a", "b", "c", "d", "e", "f", "g", "i", "j", "l", "m", "n", "o", "p", "r"};
String saveLetter = "";

public void askLetter() {
    for (int i = 0; i < letters.length; i++) {
        saveLetter += " " + letters[i] + ",";
    }
    System.out.println("Insert a word that contains these letters " + saveLetter);
    insertedLetter = ent.nextLine();

    if (saveLetter.equals(insertedLetter)) {
        System.out.println("The letter is correct");
    } else {
        System.out.println("The letter is incorrect");
    }
}

}

Answer 1

这样做的简单方法如下：

    boolean contained = true;
    for (int i = 0; i < insertedLetter.length(); i++) {
        if (saveLetter.indexOf(insertedLetter.charAt(i)) == -1) {
            contained = false;
            break;
        }
    }
    if (contained) {
        System.out.println("The letters are all contained in the saveLetter array");
    } else {
        System.out.println("One or more of the input letters are not contained in the saveLetter array");
    }

询问包含数组中包含的字母的单词

1 个答案: