使用批处理文件中的echo在单行中合并输出

Question

我想修改下面的脚本，让我像

一样

Number of processes on machine1 are 1

Number of processes on machine2 are 3

Number of processes on machine3 are 7

Number of processes on machine4 are 2

请有人帮忙吗？

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@echo off
setlocal enabledelayedexpansion

pushd "%~dp0"

echo %date% %time% 

TASKLIST /S machine1 | grep -c "process" 
TASKLIST /S machine2 | grep -c "process" 
TASKLIST /S machine3 | grep -c "process" 
TASKLIST /S machine4 | grep -c "process" 

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Answer 1

如果使用IMAGENAME命令，您可以使用过滤器为您提供必要的过程。 我使用了for命令，因为IMAGENAME的输出表现很奇怪......它总是显示在行的开头。

@echo off 
set compName1=machine1
for /f %%a in ('tasklist /NH /FO CSV /FI "IMAGENAME eq process" ^| find /C /V ""') do (
    echo Number of processes on %compName1% are %%a
)