#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
int main()
{
FILE *file,*fileout;
unsigned char data[1];
uint8_t what[] = {0x00, 0xEB, 0x00, 0x00, 0x50, 0xE3, 0x02};
uint8_t repl[] = {0x00, 0xEB, 0x01, 0x00, 0x37, 0xB3, 0x02};
uint8_t *buf_find(uint8_t *p, uint8_t *end, uint8_t *needle, int len)
{
end = end - len + 1;
while (p < end) {
if (memcmp(p, needle, len) == 0) return p;
p++;
}
return NULL;
}
file=fopen("test.bin","rb");
fileout=fopen("test.bin.bak","wb");
while (!feof(file)) {
if (fread(data, 1, 1, file) > 0) {
char *p = data;
char *end = data + 1;
for (;;) {
uint8_t *q = buf_find(p, end, what, sizeof(what));
if (q == NULL) break;
memcpy(q, repl, sizeof(repl));
p = q + sizeof(data[0]);
}
printf("%02X ",data[0]);
fwrite(&data,1,1,fileout);
}
}
fclose(file);
fclose(fileout);
return 0;
}
如何更改二进制文件中的二进制文件十六进制字符? 读取十六进制=“00 EB 00 00 50 E3 02”替换hex =“00 EB 01 00 37 E3 02”
我的问题得到了回答,但这很慢。 Hexadecimal find and replace
答案 0 :(得分:1)
试试这个
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
size_t replace(FILE *fi, FILE *fo, uint8_t *what, uint8_t *repl, size_t size){
size_t i, index = 0, count = 0;
int ch;
while(EOF!=(ch=fgetc(fi))){
if(ch == what[index]){
if(++index == size){
for(i = 0; i < size ; ++i){
fputc(repl[i], fo);
}
index = 0;
++count;
}
} else {
for(i = 0; i < index ; ++i){
fputc(what[i], fo);
}
index =0;
fputc(ch, fo);
}
}
for(i = 0; i < index ; ++i){
fputc(what[i], fo);
}
return count;
}
int main(void){
FILE *file,*fileout;
uint8_t what[] = {0x00, 0xEB, 0x00, 0x00, 0x50, 0xE3, 0x02};
uint8_t repl[] = {0x00, 0xEB, 0x01, 0x00, 0x37, 0xB3, 0x02};
size_t count;
file=fopen("test.bin","rb");
fileout=fopen("test.bin.bak","wb");
count = replace(file, fileout, what, repl, sizeof(what));
printf("number of replace count is %zu\n", count);
fclose(fileout);
fclose(file);
return 0;
}