Question

我使用此函数来解析url参数

function parseURL(url) {
    var a =  document.createElement('a');
    a.href = url;
    return {
        source: url,
        protocol: a.protocol.replace(':',''),
        host: a.hostname,
        port: a.port,
        query: a.search,
        params: (function(){
            var ret = {},
            seg = a.search.replace(/^\?/,'').split('&'),
            len = seg.length, i = 0, s;
            for (;i<len;i++) {
                if (!seg[i]) { continue; }
                s = seg[i].split('=');
                ret[s[0]] = s[1];
            }
            return ret;
        })(),
        file: (a.pathname.match(/\/([^\/?#]+)$/i) || [,''])[1],
        hash: a.hash.replace('#',''),
        path: a.pathname.replace(/^([^\/])/,'/$1'),
        relative: (a.href.match(/tps?:\/\/[^\/]+(.+)/) || [,''])[1],
        segments: a.pathname.replace(/^\//,'').split('/')
    };
}

我可以通过以下方式调用此函数：

var currentURL = parseURL(window.location.href);
console.log(currentURL.params['price']);

但我想弄清楚params的长度......以验证是否已经有任何参数。

console.log(currentURL.params.length) // doesn't work -> returns undefined

现在你问我：为什么你想知道长度？因为我有另一个功能：

function filter(type, currentURL){
    var result = "";
    var url    = document.location.href;

    if(currentURL.params[type] != undefined){
        var price   = currentURL.params[type];

        if(url.indexOf('&' + type + '=asc') > 0){
            result = url.replace("&" + type + "=asc", "&" + type + "=desc");
        }else if(url.indexOf("?" + type + "=asc") > 0){
            result = url.replace("?" + type + "=asc", "?" + type + "=desc");
        }else if(url.indexOf("&" + type + "=desc") > 0){
            result = url.replace("&" + type + "=desc", "&" + type + "=asc");
        }else if(url.indexOf("?" + type + "=desc") > 0){
            result = url.replace("?" + type + "=desc", "?" + type + "=asc");
        }
    }else{
        result = url + "&" + type + "=asc";
        if(currentURL.length == 0){
            // The problem is here
            result = url + "?" + type + "=asc";
        }
    }

    return result;
}

因为如果我没有参数，我应该放置：index.php?price=asc而不是index.php&price=asc。

使用@Pointy帮助编辑：解决。

result = url + "&" + type + "=asc";
if(window.location.search.length == 0){
   result = url + "?" + type + "=asc";
}

Answer 1

除非您明确制作一个数组和字符串，否则只有length 相反，您可以拨打Object.keys(x).length。

Javascript解析URL检测长度

1 个答案: