Question

我的功能如下：

function_dictionary = {'get_user_from_id': (requests.get,                           #Function
                                           (url + "/users/" + str(user_id),),       #Tuple of Arguments
                                           {'headers': headers}),                   #Dictionary of keyword args

                           'get_user_from_username': (requests.get,
                                            (url + "/users?username=" + str(user_id),),
                                            {'headers': headers}),

                           'get_user_from_email': (requests.get,
                                         (url + "/users?email=" + str(user_id),),
                                         {'headers': headers}),

                           'delete': (requests.delete,
                                      (url + "/users/" + str(user_id),),
                                      {'headers': headers}),

                           'patch_user':(requests.patch,
                                         (url + "/users/" + str(user["ID"]),),
                                         {'headers': headers, 'data':json.dumps(user)}),

                           'post': (requests.post,
                                    (url + "/users" ,),
                                    {'headers': headers,'data':json.dumps(user)})
                           }

func, args, kwargs = function_dictionary[request]

func(*args, **kwargs)

result = func(*args, **kwargs)

我需要记录即将执行的确切代码行。在一个完美的世界里，我正在寻找这样的东西：

print func(*args, **kwargs).toString or str(func(*args, **kwargs)

有人知道我想做什么是可能的还是我应该专注于自己构建一个字符串？

干杯！

Answer 1

对于您的情况，您可以简单地执行

print func.func_name, args, kwargs

如果我自己定义函数，我会写一个通用装饰器，就像这个

def decorate_logger(func):
    def inner(*args, **kwargs):
        print "Entering", func.func_name, "with Parameters :", args, kwargs
        temp = func(*args, **kwargs)
        print "Leaving ", func.func_name, "with :", temp, "for :", args, kwargs
        return temp
    return inner

@decorate_logger
def sum(a, b, c):
    return a + b + c

print sum(1, 2, 3)
print sum(1, 2, c = 3)

<强>输出

Entering sum with Parameters : (1, 2, 3) {}
Leaving  sum with : 6 for : (1, 2, 3) {}
6
Entering sum with Parameters : (1, 2) {'c': 3}
Leaving  sum with : 6 for : (1, 2) {'c': 3}
6

将函数及其参数打印为字符串

1 个答案: