我有表说VendorReport在这个表中我有三列ID,PrefixId,Download_date 我表中的数据如下
ID PrefixId Download_date
1 VIS017 28-09-2012
2 VIS028 29-09-2012
3 VIS035 29-09-2012
4 VIS028 30-09-2012
5 VIS028 29-09-2012
6 VIS028 01-10-2012
7 VIS025 30-09-2012
我想要具有最小日期的唯一PrefixId记录,如下所示
1 VIS017 28-09-2012
2 VIS028 29-09-2012
3 VIS035 29-09-2012
4 VIS025 30-09-2012
所以我尝试了这个查询但没有得到预期的结果。
select VendorReport.PrefixId,VendorReport.Download_Date from VendorReport
join (select PrefixId, MIN(Download_Date) d_date from VendorReport group by PrefixId) t2 on VendorReport.PrefixId= t2.PrefixId order by VendorReport.Download_Date asc
答案 0 :(得分:1)
我是sql server的新手,请试试这个
select prefixId,min(download_date) as download_date from #abc group by prefixId order by prefixId asc
答案 1 :(得分:0)
试试这个..............
select Row_number() over ( order by x.Download_date),x.PrefixId,x.Download_date
(
select PrefixId,Min(Download_date) Download_date
from
VendorReport
group by Prefixid
) x
答案 2 :(得分:0)
你去吧
create table #VendorReport(
ID int,
PrefixId nvarchar(50),
Download_date datetime
)
insert into #VendorReport values(1,'IS017','2012-09-28');
insert into #VendorReport values(2,'IS028','2012-09-29');
insert into #VendorReport values(3,'IS035','2012-09-29');
insert into #VendorReport values(4,'IS028','2012-09-30');
insert into #VendorReport values(5,'IS028','2012-09-29');
insert into #VendorReport values(6,'IS028','2012-10-01');
insert into #VendorReport values(7,'IS025','2012-09-30');
select * from #VendorReport
select ROW_NUMBER() OVER(ORDER BY PrefixId) as Id, PrefixId, min(Download_date) as Download_date from #VendorReport group by PrefixId
drop table #VendorReport
答案 3 :(得分:0)
目前尚不清楚你想要得到什么。希望这会有所帮助:
WITH T AS
(
select
VendorReport.*,
ROW_NUMBER() OVER (PARTITION BY PrefixID
ORDER BY Download_date, ID) as RowNum
from VendorReport
)
SELECT ID,PrefixId, Download_date
FROM T
WHERE RowNum=1
Order by Download_Date DESC