我想在查询中获取给定孩子下面所有孩子的详细信息 例如。 如果我给出等级4或(等级N)那么我想得到所有等级的所有细节(如L1到L4 / LN)
答案 0 :(得分:2)
Found the answer from this Link
DROP TABLE IF EXISTS pctable;
CREATE TABLE pctable
(
id INT NOT NULL AUTO_INCREMENT,
parent_id INT,
PRIMARY KEY (id)
) ENGINE=MyISAM;
INSERT INTO pctable (parent_id) VALUES (0);
INSERT INTO pctable (parent_id) SELECT parent_id+1 FROM pctable;
INSERT INTO pctable (parent_id) SELECT parent_id+2 FROM pctable;
INSERT INTO pctable (parent_id) SELECT parent_id+3 FROM pctable;
INSERT INTO pctable (parent_id) SELECT parent_id+4 FROM pctable;
INSERT INTO pctable (parent_id) SELECT parent_id+5 FROM pctable;
SELECT * FROM pctable;
DELIMITER $$
DROP FUNCTION IF EXISTS `GetFamilyTree1` $$
CREATE FUNCTION `GetFamilyTree1` (GivenID INT) RETURNS varchar(1024) CHARSET latin1
DETERMINISTIC
BEGIN
DECLARE rv,q,queue,queue_children VARCHAR(1024);
DECLARE queue_length,front_id,pos INT;
SET rv = '';
SET queue = GivenID;
SET queue_length = 1;
WHILE queue_length > 0 DO
SET front_id = FORMAT(queue,0);
IF queue_length = 1 THEN
SET queue = '';
ELSE
SET pos = LOCATE(',',queue) + 1;
SET q = SUBSTR(queue,pos);
SET queue = q;
END IF;
SET queue_length = queue_length - 1;
SELECT IFNULL(qc,'') INTO queue_children
FROM (SELECT GROUP_CONCAT(id) qc
FROM pctable WHERE parent_id = front_id) A ;
IF LENGTH(queue_children) = 0 THEN
IF LENGTH(queue) = 0 THEN
SET queue_length = 0;
END IF;
ELSE
IF LENGTH(rv) = 0 THEN
SET rv = queue_children;
ELSE
SET rv = CONCAT(rv,',',queue_children);
END IF;
IF LENGTH(queue) = 0 THEN
SET queue = queue_children;
ELSE
SET queue = CONCAT(queue,',',queue_children);
END IF;
SET queue_length = LENGTH(queue) - LENGTH(REPLACE(queue,',','')) + 1;
END IF;
END WHILE;
RETURN rv;
END $$
DELIMITER ;
SELECT id,GetFamilyTree1(id) FROM pctable where id = 2;
****以上查询将给出id为2的孩子。****
2天后我得到解决方案..: - )
答案 1 :(得分:0)
我认为您的第n级查询可以使用SELF JOIN Like
来完成SELECT a.name, b.name FROM clildparent a, clildparent b WHERE a.id = b.parent_id;
认为它会有所帮助!!