Question

我尝试使用Hibernate 4.1.6和Spring 3.0.5创建Java程序。当我运行我的应用程序时抛出NULLPOINT EXCEPTION。任何人都可以帮助我，

SpringBeans.xml：

http://www.springframework.org/schema/beans/spring-beans-3.1.xsd“＆GT;

<!-- Database Configuration -->
<import resource="config/spring/DataSource.xml"/>
<import resource="config/spring/HibernateSessionFactory.xml"/>

<!-- Beans Declaration -->
<import resource="config/spring/UserBeans.xml"/>

2. HibernateSessionFactory.xml

<property name="dataSource">
  <ref bean="dataSource"/>
</property>

<property name="hibernateProperties">
   <props>
     <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
     <prop key="hibernate.show_sql">true</prop>
   </props>
</property>

<property name="mappingResources">
    <list>
      <value>com/model/TblUser.hbm.xml</value>
    </list>
</property>

DataSource.xml

WEB-INF /班/配置/数据库/属性/ database.properties
database.properties

jdbc.driverClassName = com.mysql.jdbc.Driver jdbc.url = JDBC：MySQL的：本地主机：3306 / auction_nms jdbc.username =根 jdbc.password =根
UserBeans.xml
```

```

UserDaoImpl .java

public class UserDaoImpl实现UserDao { @Autowired SessionFactory sessionFactory;

/*
 * @see com.dao.UserDao#save(com.model.TblUser)
 */
@Override
public void save(TblUser user) {
    sessionFactory.getCurrentSession().save(user);
}

7.App.java

public class App {

    // get log4j handler
    private static final Logger logger = Logger.getLogger(App.class);

    static TblUser              user   = new TblUser(2, "2", "2");

    public static void main(String[] args) {
        try {
            UserDao userDao = new UserDaoImpl();
            userDao.save(user);
        } catch (Exception e) {
            System.err.`enter code here`println(e);
        } finally {
            if (logger.isDebugEnabled()) {
                logger.debug(user);
            }
        }
    }
}

非常感谢!!!

Answer 1

您正在使用UserDAO关键字创建new对象。您应该通过加载appContext来启动spring容器，在您的情况SpringBeans.xml中。如果您使用new关键字Spring并不管理您的依赖项，那么，您的sessionFactory永远不会注入DAO实例。

这应该是您main()的内容，而不是当前的内容。

ApplicationContext appContext = new ClassPathXmlApplicationContext(new String[] {
        "classpath*:/META-INF/SpringBeans.xml"
        });
appContext.getBean("userDao");

..打电话给你保存。

使用Hibernate 4和Spring 3.0.5集成的NullPointErexception

1 个答案: