Question

我有以下表格用户（id，name，email），文章（id，user_id，title，body）。我似乎无法使用登录的user_id填充articles表中的user_id。这是我的代码 //文章控制器

    public function add() {
    if ($this->request->is('post')) {
    $this->Article->create();
    $this->request->data['Article']['user_id'] = $user_id;
    if ($this->Article->save($this->request->data)) {
    $this->Session->setFlash(__('The article has been saved.'));
    return $this->redirect(array('action' => 'index'));
    } else {
    $this->Session->setFlash(__('The article could not be saved. Please, try again.'));
    }
    }
    $users = $this->Article->User->find('list');
    $this->set(compact('users'));
    }

上述方法在文章

中返回user_id的空值

我也尝试从视图中检索：

    echo $this->Form->hidden('user_id', arrray('value' => $userAuth['id']));

我收到以下错误语法错误，意外'=＆gt;' （T_DOUBLE_ARROW）

Answer 1

echo $this->Form->hidden('user_id', arrray('value' => $userAuth['id']));

应该是，

echo $this->Form->hidden('user_id', array('value' => $userAuth['id']));

阵列中的错字（R的3倍）。

Answer 2

试试这个：

public function add() {
    if ($this->request->is('post')) {
       $this->Article->create();
       if ($this->Article->save($this->request->data)) {
          $this->Session->setFlash(__('The article has been saved.'));
          return $this->redirect(array('action' => 'index'));
       } else {
          $this->Session->setFlash(__('The article could not be saved. Please, try again.'));
    }
    else{
        $this->set('user_id', $userAuth['id']);
        $users = $this->Article->User->find('list');
        $this->set(compact('users'));
    }
}

视图中的

echo $this->Form->hidden('Article.user_id', arrray('value' => $user_id));

但是我不知道你在哪里设置$userAuth，在获得它的值之前分配这个变量是安全的

在不同的表中将当前user_id指定为外部值

2 个答案: