Question

我有执行查询的网址。

https://<BASE_URL>/<TENANT_URL>/?query=where UserName='abc'&companyId=&page=1&pageSize=25&filterResultByColumns=true

我在租客网址之后逃离剩下的部分，

 NSString *requestUrl = [[NSString stringWithFormat:@"%@/?query=where UserName='%@'&companyId=&page=1&pageSize=25&filterResultByColumns=true",<TENANT_URL>,userCredential.userName]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    requestUrl = [NSString stringWithFormat:@"%@/%@",baseurl,requestUrl];

这是我的GET请求。

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
        AFHTTPResponseSerializer *serializer = [AFHTTPResponseSerializer serializer];

            serializer.acceptableContentTypes = [NSSet setWithObject:@"application/json"];


        manager.responseSerializer = serializer;
        manager.requestSerializer = [AFJSONRequestSerializer serializer];
    NSString *path = [NSString stringWithFormat:@"%@",URL];


    [manager GET:path parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
                    NSError* error = nil;
                    NSArray* json = [NSJSONSerialization
                                          JSONObjectWithData:responseObject

                                          options:kNilOptions 
                                          error:&error];
                    success(json);
                }
                     failure:^(AFHTTPRequestOperation *operation, NSError *error) {
                         failure(error);
                     }];

但我总是收到400 Bad request错误。我认为问题在于“query = where ..”。但我不确定。我该如何解析URL。我在Chrome中使用“POSTMAN”进行了测试。它完美地运作。但是当我运行应用程序时，它会引发错误。

错误：

Error Domain=AFNetworkingErrorDomain Code=-1011 "Request failed: bad request (400)" UserInfo=0xb7ac2b0 {NSErrorFailingURLKey=https://<BASE_URL>/<TENANT_URL>/?query=where UserName='abc'&companyId=&page=1&pageSize=25&filterResultByColumns=true&url=https%3A%2F%2F<BASE_URL>%2F%2F<TENANT_URL>%2F%3F?query=where%2DUserName%3D%27abc%27%26companyId%3D%26page%3D1%26pageSize%3D25%26filterResultByColumns%3Dtrue, AFNetworkingOperationFailingURLResponseErrorKey=<NSHTTPURLResponse: 0xb7e6910> { URL: https://<BASE_URL>/<TENANT_URL>/?query=where UserName='abc'&companyId=&page=1&pageSize=25&filterResultByColumns=true&url=https%3A%2F%2F<BASE_URL>%2F%2F<TENANT_URL>%2F%3F?query=where%2DUserName%3D%27abc%27%26companyId%3D%26page%3D1%26pageSize%3D25%26filterResultByColumns%3Dtrue } { status code: 400, headers {
    "Cache-Control" = private;
    "Content-Length" = 0;
    "Content-Type" = "text/html";
    Date = "Fri, 17 Jan 2014 05:29:56 GMT";
    Server = "Microsoft-HTTPAPI/2.0";
    "X-AspNet-Version" = "4.0.30319";
    "X-Powered-By" = "ASP.NET";
} }, NSLocalizedDescription=Request failed: bad request (400)}

Answer 1

看起来您正在构建的URL存在许多问题，以及您将参数传递（或未传递）到AFNetworking的方式。您不需要自己构建查询字符串，因为AFNetworking会为您执行此操作。正如我在上面的评论中所提到的，将query=where UserName='abc'作为URL的一部分传递似乎是一个坏主意。不过，这里有一个简单示例，说明如果您的网址略有不同，您将如何调用AFNetworking的GET方法：

// URL format: https://<BASE_URL>/<TENANT_URL>/?username=abc&companyId=&page=1&pageSize=25&filterResultByColumns=true

NSURL *baseURL = [NSURL URLWithScheme:@"https" host:BASE_URL path:TENANT_URL];

[manager GET:[baseURL absoluteString] 
  parameters:@{ @"username": @"abc",
                @"companyId": @"example",
                @"page": @1,
                @"pageSize": @25,
                @"filterResultByColumns": @YES }
     success:^(AFHTTPRequestOperation *operation, id responseObject) {
            // handle success
            }
     failure:^(AFHTTPRequestOperation *operation, NSError *error) {
            // handle failure
            }];

如果您将参数传递给GET方法，AFNetworking将为您构建查询字符串。

使用afnetworking在GET方法中传递url中的参数

1 个答案: