Question

我有一个test.html页面，这里是代码。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
    <head>
    </head>
    <body>
        <span id="test" onMouseover="alert('1')">this is new one</span>
    </body>
</html>

我想使用Selenium JavascriptExecutor在测试页面中模拟跨越事件的鼠标，所以我写了这样的代码：

@Test
public void testJSExecutor(){
    System.setProperty("webdriver.firefox.bin", "C:\\Program Files (x86)\\Mozilla Firefox\\firefox.exe");
    webDriver = new FirefoxDriver();
    webDriver.get("file:\\\\C:/test.html");

    String script = "function test(){var t=document.getElementById('test');"
            + "if( document.createEvent ) {"
            + "var evObj = document.createEvent('MouseEvents');"
            + "evObj.initEvent( 'mouseover', true, false );"
            + "elem.dispatchEvent(evObj);"
            +"} else if( document.createEventObject ) {"
            + "elem.fireEvent('onmouseover');"
            +"}} window.onload=test;";
    jsExecutor = (JavascriptExecutor) webDriver;
    jsExecutor.executeScript(script);
}

但运行此代码后，没有提示提示。

鼠标悬停事件如何有效，以便提示警报？

Answer 1

您可以使用以下代码模拟鼠标悬停操作..

Actions actions = new Actions(driver);
WebElement menuHoverLink = driver.findElement(By.id("test"));
actions.moveToElement(menuHoverLink);
actions.perform();

如何在Selenium JavascriptExecutor中执行脚本

1 个答案: