Question

我正在查询一年中一个人拼车的次数，按季度细分。每次这个人拼车20次，他们就有资格获得报酬。拼车数量全年继续累计，但每季度只支付一次。

我有这样的数据：

+-------+-----+--------+----+
|quarter|value|RunTotal|Paid|
+-------+-----+--------+----+
|Jan-Mar|19.0 |19.0    |0.00|
+-------+-----+--------+----+
|Apr-Jun|2.0  |21.0    |1.00|
+-------+-----+--------+----+
|Jul-Sep|0.0  |21.0    |0.00|
+-------+-----+--------+----+
|Oct-Dec|0.0  |21.0    |0.00|
+-------+-----+--------+----+

如图所示，他们在第一季度没有得到支票。然而，他们在第二次做到了。我可以计算出总的罚款。但是，我需要在付费列中执行总计，减去之前的任何支出。请看一下，给我一些帮助。

DECLARE @SalesTbl TABLE (quarter varchar(250), value decimal(18,1), RunningTotal decimal(18,1), earned money)
DECLARE @RunningTotal decimal(18,1), @earned money
SET @RunningTotal = 0
SET @earned = 0

INSERT INTO @SalesTbl 
    SELECT CASE DatePart(q, c.date) 
    WHEN 1 THEN 'Jan-Mar' 
    WHEN 2 THEN 'Apr-Jun' 
    WHEN 3 THEN 'Jul-Sep' 
    WHEN 4 THEN 'Oct-Dec' END AS quarter,
    IsNULL(Sum(t.value),0) AS value,
    null,
    0
FROM @calendar c
LEFT OUTER JOIN events e ON (DatePart(q, c.date) = DatePart(q, e.eventDate) AND e.employeeID = @employeeID AND e.eventType = 'CP' AND Year(eventDate) = @year)
LEFT JOIN types t ON t.typeID = e.eventType
GROUP BY DatePart(q, c.date)

UPDATE @SalesTbl 
SET @RunningTotal = RunningTotal = @RunningTotal + value, @earned = earned = Floor(@RunningTotal/20) - (SELECT Sum(earned) FROM @SalesTbl)

FROM @SalesTbl

SELECT * FROM @SalesTbl

Answer 1

听起来你应该使用SQL窗口

有关示例，请参阅以下页面： http://technet.microsoft.com/en-us/library/ms189461.aspx

您应该按季度（DatePart（q，c.date））和SUM（t.value）进行分区。 SUM（SUM（t.value））OVER（PARTITION BY DatePart（q，c.date））AS'Total'

SQL运行总量在x量后重置

1 个答案: