Question

令人惊讶的是，我发现这个主题几乎没有，但我认为这是一个非常简单的解决方案。

问题描述：

我有一个Javascript变量，它填充了一个PHP变量：

var createdEncode = '<?php echo $createdEncode; ?>';

PHP包含一个JSON字符串，但没有开始和结束的花括号。我检查了分隔符问题但是我觉得这个字符串很好，亲眼看看：

var createdEncode = '"sEcho":1,"iTotalRecords":15,"iTotalDisplayRecords":11,"aaData":[["1","Suche Kurier","","dauerhaft, immer","","","ein geschenk","3","test dauerhaft","0","1","1","",""],["4","Suche Hilfe","1","bis 09.01.2014, sdfkdsjf","","","Du gibst:  9\u20ac","1","Auch gibt es niemanden, der den Schmerz an sich liebt, sucht ...","1","1","0","",""],["5","Suche Kurier","","bis 15.01.2014, jklkl","","","Du gibst:  8\u20ac","1","jllk","1","1","0","",""],["7","Suche Kurier","","bis 20.01.2014, jkljkl","","","Du gibst:  8\u20ac","1","nm,.","0","1","0","",""],["8","Suche Hilfe","1","am 25.01.2014 um 08:45 Uhr","","","Du gibst:  8\u20ac\/h","2","dsdf","0","1","0","",""],["9","Biete Kurier","","bis 08.01.2014, swrslkjk","","","kljkjl","3","Auto Kompaktklasse, H\u00e4lfte des Kofferraums freier Platz","1","1","0","2","4"],["10","Biete Hilfe","1","am 26.01.2014 um 12:45 Uhr","","","Du bekommst:  6\u20ac","1","sdsdfs","0","1","0","",""],["11","Suche Kurier","","bis 23.01.2014, sfui","","","Du gibst:  7\u20ac","1","jlkkjl","0","1","0","",""],["12","Suche Hilfe","1","am 15.01.2014 um 13:00 Uhr","","","Du gibst:  8\u20ac\/h","2","sdfkl","1","1","0","",""],["13","Biete Kurier","","bis 29.01.2014, erert","","","Du bekommst:  4\u20ac\/h","2","Zu Fu\u00df, Dreiviertel des Kofferraums freier Platz","0","1","0","0","5"],["14","Biete Hilfe","1","dauerhaft, dfgdf","","","Du bekommst:  3\u20ac\/h","2","xfsfds\u00f6k","0","1","0","",""]],"oLanguage":{"sUrl":"language\/dataTables.german.txt"}';

后来我得到了一些JS说：

$('#postsCreatedData').dataTable({
    createdEncode,
    "bAutoWidth": false,
    "aoColumnDefs":[
        {"aTargets .... stuff ...

我的问题是“createdEncode”什么也没做，控制台抛出Uncaught SyntaxError: Unexpected token ,。 Meant是“createdEncode”之后的逗号。

我的方法：

我试过了 document.write(createdEncode);它会抛出unexpected token .。还尝试了+ createdEncode +。同样的事情，意外+ ... 我真的不知道该怎么做。你能为我提供一个解决方案，将该变量的内容打印到该数据表吗？

非常感谢。

解决方案：

由于Javascript需要一个合适的对象而不是一个字符串才能按预期工作，我必须重写完整的datatable（） - 调用。感谢MueR让我走上正轨。

基本上我将打印的PHP变量转换为标准的JSON对象，并将其与我设置为变量的其他选项一起扩展为JSON对象。

我所做的就是：

var createdParams = $.extend({}, createdEncode, appendix);将“附录”-JSON插入createdEncode，因此调用现在适用于：

$('#postsCreatedData').dataTable(createdParams);

Answer 1

你的问题是你在那个对象中放了一个字符串（没有键），这是无效的。您生成的javascript是

{
    "a string without index, which is illegal",
    "bAutoWidth": false,
        "aoColumnDefs":[]
}

要正确地执行此操作，您需要让PHP也包括括号，而不是周围的单引号，因此它是一个实际的对象。然后，您必须将createdEncode与包含bAutoWidth等的其他对象合并。

你可以试试这个（假设你让PHP输出一个真正的javascript对象）

var dataTableParams = $.extend({}, createdEncode, {"bAutoWidth": false, .. other things ..});

在括号中打印javascript变量

1 个答案: