我对更改XML文件以创建带表的html文件感兴趣。
这是原始XML
的示例<?xml version="1.0" encoding="UTF-8"?>
<library xmlns:dc="http://purl.org/dc/elements/1.1/">
<item>
<title>Electronic Payments for State Taxes and Fees</title>
<link>http://mesharpe.metapress.com/link.asp?id=T861142L5675QQW2</link>
<dc:identifier>DOI 10.2753/PMR1530-9576360406</dc:identifier>
</item>
<item>
<title>The Determinants of Union Attitudes among Community College Professors</title>
<link>http://baywood.metapress.com/link.asp?id=R216M2L6263165N1</link>
<dc:identifier>DOI 10.2190/CN.32.4.a</dc:identifier>
</item>
<item>
<title>Using Dedicated Nurses to Improve Core Measures Compliance</title>
<link>http://rss.sciencedirect.com/...link>
<dc:identifier>http://rss.sciencedirect.com/...</dc:identifier>
</item>
</library>
我想创建这样的东西:
<?xml version="1.0" encoding="UTF-8"?>
<html xmlns:h="http://purl.org/rss/1.0/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:prism="http://prismstandard.org/namespaces/1.2/basic/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:mn="http://usefulinc.com/rss/manifest/" xmlns:content="http://purl.org/rss/1.0/modules/content/">
<body>
<h1 align="center">Something</h1>
<table border="1" width="700" align="center">
<tr bgcolor="#CC661F">
<th>Title</th>
<th>Identifier</th>
</tr>
<tr>
<td>Electronic Payments for State Taxes and Fees</td>
<td>http://dx.doi.org/10.2753/PMR1530-9576360406</td>
</tr>
<tr>
<td>The Determinants of Union Attitudes among Community College Professors</td>
<td>http://dx.doi.org/10.2190/CN.32.4.a</td>
</tr>
<tr>
<td>Using Dedicated Nurses to Improve Core Measures Compliance</td>
<td>http://rss.sciencedirect.com/...</td>
</tr>
</table>
</body>
</html>
因此对于字段 dc:identifier ,有一个链接或带有数字的DOI。对于每个有DOI的人,我想删除DOI和空格,然后在前面添加http://dx.doi.org/,从而在表格中创建一个链接。
有关如何完成此任务的任何提示?谢谢!
编辑:我以前从未使用过XSLT文件而且我只有一个准系统模板:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:h="http://purl.org/rss/1.0/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:prism="http://prismstandard.org/namespaces/1.2/basic/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:mn="http://usefulinc.com/rss/manifest/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
<html>
<body>
<h1 align="center">Title</h1>
<table border="1" width="700" align="center">
<tr bgcolor="#CC661F">
<th>Title</th>
<th>Link</th>
</tr>
<xsl:for-each select="//h:item">
<tr>
<td>
<xsl:value-of select="h:title" disable-output-escaping="yes"/>
</td>
<td>
<xsl:value-of select="dc:identifier"/>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
答案 0 :(得分:0)
您应该利用XSLT的模板匹配机制,而不是尝试使用for-each
。
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:h="http://purl.org/rss/1.0/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:prism="http://prismstandard.org/namespaces/1.2/basic/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:mn="http://usefulinc.com/rss/manifest/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/">
<html>
<body>
<h1 align="center">Title</h1>
<table border="1" width="700" align="center">
<tr bgcolor="#CC661F">
<th>Title</th>
<th>Link</th>
</tr>
<xsl:apply-templates select="//h:item" />
</table>
</body>
</html>
</xsl:template>
<!-- create one row for each item -->
<xsl:template match="h:item">
<tr>
<xsl:apply-templates select="h:title | dc:identifier" />
</tr>
</xsl:template>
<!-- title and identifier become table columns -->
<xsl:template match="h:title | dc:identifier">
<td><xsl:apply-templates /></td>
</xsl:template>
<!-- text nodes that start DOI are massaged to add the appropriate prefix -->
<xsl:template match="text()[starts-with(., 'DOI ')]">
<xsl:value-of select="concat('http://dx.doi.org/', substring(., 5))" />
</xsl:template>
</xsl:stylesheet>
这里的诀窍是处理文本节点的默认模板只是打印出节点的值,我在这里做的是添加一个额外的模板,仅用于启动“DOI”以添加http://dx.doi.org/
前缀的文本节点