我正在编写一个2D矩阵模板来学习模板和一些C ++ 11的功能。
写下以下标题:
template <class T, unsigned int Rows, unsigned int Columns>
class Matrix2D
{
private:
array<array<T,Columns>, Rows> m_Matrix;
public:
Matrix2D() {}
array<T,Columns>& operator[](unsigned int row) { return m_Matrix[row]; } ;
const array<T,Columns>& operator[](unsigned int row) const { return m_Matrix[row]; } ;
friend Matrix2D operator+ <> (const Matrix2D &lhs, const Matrix2D &rhs);
friend Matrix2D operator* <> (const Matrix2D &lhs, const Matrix2D &rhs);
};
operator+
工作正常 - 我有一个实现,它编译,链接,并通过调试器。
问题在于operator*
,我得到了编译错误
1>...\matrix2d.h(18): error C2143: syntax error : missing ';' before '<'
1>...\matrix2d.h(19) : see reference to class template instantiation 'Matrix2D<T,Rows,Columns>' being compiled
尝试使用运算符没有代码行,所以定义本身是错误的,我只是不明白为什么。
有人可以帮忙吗?
编辑 :( 从评论中添加)
template <class T, unsigned int Rows, unsigned int Columns>
Matrix2D<T, Rows, Columns> operator+ (const Matrix2D<T, Rows, Columns> &lhs, const Matrix2D<T, Rows, Columns> &rhs)
{
Matrix2D<T, Rows, Columns> addResult;
for (unsigned int i = 0; i < Rows; i++)
for (unsigned int j = 0; j < Columns; j++)
addResult[i][j] = lhs[i][j] + rhs[i][j];
return addResult;
}
template <class T, unsigned int Rows, unsigned int Columns>
Matrix2D<T, Rows, Columns> operator* (const Matrix2D<T, lRows, lColumns> &lhs, const Matrix2D<T, rRows, rColumns> &rhs)
{
Matrix2D<T, lRows, rColumns> mulResult;
for(unsigned int i = 0; i < lRows; i++)
for(unsigned int j = 0; j < rColumns; j++)
for (unsigned int k = 0; k < lColumns; k++)
mulResult[i][k] += lhs[i][k] * rhs[k][j];
return addResult;
}
答案 0 :(得分:2)
您无法与未声明的模板功能进行专业化。当然,在定义类模板之前声明运算符将要求您转发声明它:
template <class T, unsigned int Rows, unsigned int Columns>
class Matrix2D;
template <class T, unsigned int Rows, unsigned int Columns>
Matrix2D<T, Rows, Columns>
operator+ (const Matrix2D<T, Rows, Columns> &lhs, const Matrix2D<T, Rows, Columns> &rhs);
template <class T, unsigned int Rows, unsigned int Columns>
Matrix2D<T, Rows, Columns>
operator* (const Matrix2D<T, Rows, Columns> &lhs, const Matrix2D<T, Rows, Columns> &rhs);
template <class T, unsigned int Rows, unsigned int Columns>
class Matrix2D
{
private:
array<array<T,Columns>, Rows> m_Matrix;
public:
Matrix2D() {}
array<T,Columns>& operator[](unsigned int row) { return m_Matrix[row]; }
const array<T,Columns>& operator[](unsigned int row) const { return m_Matrix[row]; }
friend Matrix2D operator+ <> (const Matrix2D &lhs, const Matrix2D &rhs);
friend Matrix2D operator* <> (const Matrix2D &lhs, const Matrix2D &rhs);
};
或者,您可以采用简单的方法为Matrix2D
的每个专业化定义单独的运算符函数:
template <class T, unsigned int Rows, unsigned int Columns>
class Matrix2D
{
private:
array<array<T,Columns>, Rows> m_Matrix;
public:
Matrix2D() {}
array<T,Columns>& operator[](unsigned int row) { return m_Matrix[row]; }
const array<T,Columns>& operator[](unsigned int row) const { return m_Matrix[row]; }
friend Matrix2D operator+ (const Matrix2D &lhs, const Matrix2D &rhs) {
// do stuff that adds.
}
friend Matrix2D operator* (const Matrix2D &lhs, const Matrix2D &rhs) {
// do stuff that multiplies.
}
};
我可能会使用更简单的整体语法。
编辑:非正方形矩阵的正确乘法意味着operator*
函数实际上需要成为Matrix2D
的三个不同特化的朋友:左操作数的类型,右操作数和结果。我认为这里的第一种方法会变得站不住脚。您应该成为operator*
的所有专精的朋友:
template <class T, unsigned int Rows, unsigned int Columns>
class Matrix2D
{
// ...
template <typename U, typename V, unsigned Rows, unsigned Common, unsigned Columns>
friend Matrix2D<decltype(std::declval<U>()+std::declval<V>()), Rows, Columns>
operator * (const Matrix2D<U, Rows, Common>&,
const Matrix2D<V, Common, Columns>&);
};
或简单地公开数据(无论如何,这可能是“数据收集”类的最佳方法)。
答案 1 :(得分:1)
在:
template <class T, unsigned int Rows, unsigned int Columns>
class Matrix2D
{
// ...
friend Matrix2D operator* <> (const Matrix2D &lhs, const Matrix2D &rhs);
};
Matrix2D
实际上是指Matrix2D<T, Rows, Columns>
。
您的operator *
应该是
template <T, unsigned Rows1, unsigned int Common, unsigned int Column>
Matrix2D<T, Row1, Column> operator* (const Matrix2D<T, Row1, Common>& lhs, const Matrix2D<T, Common, Column>& rhs);