sum列，显示每行的总数

Question

我有一个如下所示的查询：

select Group, Sum(columnA) as SumColumn
FROM table
GROUP BY Group

我得到的结果看起来像这样

+-----+---------+
|Group|SumColumn|
+-----+---------+
|A    |10       |
+-----+---------+
|B    |20       |
+-----+---------+

如何更改/添加此内容以显示此类内容？

+-----+---------+-----------+
|Group|SumColumn|TotalColumn|
+-----+---------+-----------+
|A    |10       |30         |
+-----+---------+-----------+
|B    |20       |30         |
+-----+---------+-----------+

Answer 1

很难看出您的数据是什么样的 - 但是根据您发布的内容，这就是您想要的内容：

SELECT Name, 
       SumColumn,
       SUM(SumColumn) AS TotalColumn
FROM
(
    SELECT Group as Name, SUM(columnA) AS SumColumn
    FROM Table 
    GROUP BY Group
) T

你可能想要这个 - 取决于其他东西。

SELECT *,  
       SUM(columnA) OVER (PARTITION BY Group ORDER BY Group) AS SumColumn,
       SUM(columnA) OVER (PARTITION BY Group) AS TotalColumn
FROM TABLE

Answer 2

使用子查询：

SELECT [Group], Sum(columnA) as SumColumn, 
       TotalColumn = (SELECT SUM(columnA) FROM dbo.Table1)
FROM dbo.Table1
GROUP BY [Group]

Demo

Answer 3

您实际上可以在select语句中混合窗口函数和聚合函数。因此，您可以在没有子查询的情况下执行此操作：

select Group, Sum(columnA) as SumColumn,
       sum(sum(columnA)) over () as TotalColumns
FROM table
GROUP BY Group;

Answer 4

虽然这可能不是最有效的方法。这是我的答案。

SELECT a.*,
    (select Sum(columnA)
     FROM table) as [TotalColumn]
FROM (select Group, Sum(columnA) as SumColumn
      FROM table
      GROUP BY Group) as a

Answer 5

这很奇怪，您希望显示总列数和每行。运行总价值是我所期望的。但是如果你想这样它只是一个常数，你可以将Total SUM Value存储在变量中，然后在SLECT FROM TABLE查询中执行Select Variable。

    DECLARE @table TABLE
    (
        c1  sysname     NOT NULL
        ,c2 int         NOT NULL
    )
    INSERT INTO @table( c1, c2 )
    SELECT 'A',10 
    UNION ALL SELECT 'B',20 
    UNION ALL SELECT 'C',30

    DECLARE @tSum BIGINT
    SELECT @tSum = SUM(C2) FROM @table

    SELECT c1,c2,@tSum AS Tsum
    FROM @table

Answer 6

你好，这对我有用

select a.id,a.val1,b.val2,e.s 
from tbl1 as a 
inner join ( select c1,sum(val1) as s from tbl2 group by c1) as e
    on a.c1=e.c1

Answer 7

SELECT t.Group,t.SumColumn, 
       (SELECT SUM(a.SumColumn) 
          FROM Table a
         WHERE a.Group=t.Group) TotalColumn
FROM Table t