我正在使用带有JQUERY的AJAX来调用PHP脚本来验证用户电子邮件。但是,由于某种原因,表格即使不应该提交。我究竟做错了什么?我知道错误肯定不在我的PHP中。
我的代码:
$("#signup").submit(function() {
var error= false;
var dataString = $(this).serialize();
var email= $("#email").val().trim();
if (email != 0) {
// Run AJAX email validation and check to see if the email is already taken
$.ajax({
type: "POST",
url: "checkemail.php",
data: dataString,
async: false,
success: function(data) {
var error= false;
if (data == 'invalid') {
var invalid= 1;
}
else if (data == 'taken') {
var taken= 1;
}
if (invalid == 1) {
alert('invalid email');
error = true;
}
if (taken == 1) {
alert('email taken');
error = true;
}
if (error == true) {
return false;
}
}
});
}
});
答案 0 :(得分:2)
尝试更新这些:
$("#signup").submit(function(e) { //<----pass the event here as "e"
e.preventDefault(); //<----stops the form submission
var error= false;
var dataString = $(this).serialize();
var email= $.trim($("#email").val()); //<----use trim this way
答案 1 :(得分:0)
如果您绝对必须使用AJAX进行表单提交,这可能是更好的方法:
$('form').submit({
$.ajax({
type:'post',
url: 'someurl.php',
data: dataString,
context: this, // this here refers to the form object
success:function(data)
{
// perform your operations here
if(something_is_wrong)
{
// show message to user
}
else
{
this.submit(); // put this code in the block where all is ok
}
}
});
return false; // makes sure the form doesn't submit
});