我正在尝试在语音通话上开发一个Java应用程序。服务器端将消息中继回连接到它的所有客户端。现在问题是,即使发送消息的客户端最初也会收到消息,因为服务器会将消息中继回所有客户端,因为我们也听到了自己的声音。可以帮我解决这个问题吗?
我的服务器端代码:
import java.net.*;
import java.io.*;
import java.util.*;
public class Echo
{
public static void main(String[] args) throws Exception
{
ServerSocket serverSocket = new ServerSocket(3000);
while(true){Thread echoThread = new Thread(new EchoThread(serverSocket.accept()));
echoThread.start();}
}
}
class EchoThread implements Runnable
{
public static Collection<socket> sockets = new ArrayList<socket>();
Socket connection = null;
DataInputStream dataIn = null;
DataOutputStream dataOut = null;
public EchoThread(Socket conn) throws Exception
{
connection = conn;
dataIn = new DataInputStream(connection.getInputStream());
dataOut = new DataOutputStream(connection.getOutputStream());
sockets.add(connection);
}
public void run()
{
int bytesRead = 0;
byte[] inBytes = new byte[1];
while(bytesRead != -1)
{
try{bytesRead = dataIn.read(inBytes, 0, inBytes.length);}catch (IOException e) {}
if(bytesRead >= 0)
{
sendToAll(inBytes, bytesRead);
}
}
sockets.remove(connection);
}
public static void sendToAll(byte[] byteArray, int q)
{
Iterator<socket> sockIt = sockets.iterator();
while(sockIt.hasNext())
{
Socket temp = sockIt.next();
DataOutputStream tempOut = null;
try
{
tempOut = new DataOutputStream(temp.getOutputStream());
} catch (IOException e1)
{
// TODO Auto-generated catch block
e1.printStackTrace();
}
try{tempOut.write(byteArray, 0, q);}catch (IOException e){}
}
}
}
客户方:
客户方: 这里我有两节课。一个接收麦克风输入,将其发送到服务器,另一个接收来自服务器的数据,并从扬声器中播放该数据。
import java.io.DataOutputStream;
import java.net.*;
import javax.sound.sampled.*;
public class Program
{
public final static String SERVER = JOptionPane.showInputDialog("Please enter server ip");
public static void main(String[] args) throws Exception
{
AudioFormat af = new AudioFormat(8000.0f,8,1,true,false);
DataLine.Info info = new DataLine.Info(TargetDataLine.class, af);
TargetDataLine microphone = (TargetDataLine)AudioSystem.getLine(info);
microphone.open(af);
Socket conn = new Socket(SERVER,3000);
microphone.start();
DataOutputStream dos = new DataOutputStream(conn.getOutputStream());
int bytesRead = 0;
byte[] soundData = new byte[1];
Thread inThread = new Thread(new SoundReceiver(conn));
inThread.start();
while(bytesRead != -1)
{
bytesRead = microphone.read(soundData, 0, soundData.length);
if(bytesRead >= 0)
{
dos.write(soundData, 0, bytesRead);
}
}
System.out.println("IT IS DONE.");
}
}
声音接收器类:
import java.net.*;
import java.io.*;
import javax.sound.sampled.*;
public class SoundReceiver implements Runnable
{
Socket connection = null;
DataInputStream soundIn = null;
SourceDataLine inSpeaker = null;
public SoundReceiver(Socket conn) throws Exception
{
connection = conn;
soundIn = new DataInputStream(connection.getInputStream());
AudioFormat af = new AudioFormat(8000.0f,8,1,true,false);
DataLine.Info info = new DataLine.Info(SourceDataLine.class, af);
inSpeaker = (SourceDataLine)AudioSystem.getLine(info);
inSpeaker.open(af);
}
public void run()
{
int bytesRead = 0;
byte[] inSound = new byte[1];
inSpeaker.start();
while(bytesRead != -1)
{
try{bytesRead = soundIn.read(inSound, 0, inSound.length);} catch (Exception e){}
if(bytesRead >= 0)
{
inSpeaker.write(inSound, 0, bytesRead);
}
}
}
}
答案 0 :(得分:0)
看看我们现在检查的代码,我们想要发送数据的套接字是否与我们读取数据的套接字相同,如果是,我们跳过它。
public void run()
{
int bytesRead = 0;
byte[] inBytes = new byte[1];
while(bytesRead != -1)
{
try{bytesRead = dataIn.read(inBytes, 0, inBytes.length);}catch (IOException e) {}
if(bytesRead >= 0)
{
sendToAll(connection, inBytes, bytesRead);
}
}
sockets.remove(connection);
}
public static void sendToAll(Socket connection, byte[] byteArray, int q)
{
Iterator<socket> sockIt = sockets.iterator();
while(sockIt.hasNext())
{
Socket temp = sockIt.next();
if(connection == temp){
continue;
}
DataOutputStream tempOut = null;
try
{
tempOut = new DataOutputStream(temp.getOutputStream());
} catch (IOException e1)
{
// TODO Auto-generated catch block
e1.printStackTrace();
}
try{tempOut.write(byteArray, 0, q);}catch (IOException e){}
}
}