Sql在pubs示例数据库中查询具有最佳销售质量的商店

Question

在pubs数据库中，我想查询销售质量最高的商店。 我执行以下查询，

select stores.stor_id, sum(sales.qty) as sumqty
from stores
join sales on stores.stor_id = sales.stor_id
group by stores.stor_id, stores.stor_name

结果：

+-------+------+
|stor_id|sumqty|
+-------+------+
|6380   |8     |
+-------+------+
|7066   |125   |
+-------+------+
|7067   |90    |
+-------+------+
|7131   |130   |
+-------+------+
|7896   |60    |
+-------+------+
|8042   |80    |
+-------+------+

我需要的结果就像

+-------+------+
|stor_id|sumqty|
+-------+------+
|7131   |130   |
+-------+------+

你能提出一些建议吗？ 感谢。

Answer 1

简单来说，使用SELECT TOP 1和ORDER BY DESC

select top 1 sales.stor_id, sum(sales.qty) as sumqty
from stores
join sales on stores.stor_id = sales.stor_id
group by sales.stor_id
order by 2 desc;

无论如何，为什么你需要加入stores？我认为从sales表就足够了：

select top 1 sales.stor_id, sum(sales.qty) as sumqty
from sales
group by sales.stor_id
order by 2 desc;

如果结果有两个或多个记录作为最大值，则上述查询将失败。

用它来处理：

select sales.stor_id, MAX(sumqty) as sumqty from (select sales.stor_id, sum(sales.qty) as sumqty
from sales
group by sales.stor_id) sales

Answer 2

Select a.stor_id, max(sumqty)
From (

select sales.stor_id, sum(sales.qty) as sumqty
from stores
join sales on stores.stor_id = sales.stor_id
group by sales.stor_id

) a 
Group by a.stor_id

以防您有两个销售数量相同的商店