我有三个表t1
,t2
和t3
。
我想要的是使用t1
t1.Quantity= sum(t2.quantity) - sum(t3.quantity)
where id= $_POST['id']
如何为此写下来。
我尝试过这个..但它不起作用。
INSERT INTO Products
( `ProductID`, `ProductName`, `TotalQuantity`,
`TotalPrice`, `DateOfLastupdate` )
values
( '$ProductID', '$ProductName', '$Quantity',
'$TotalPrice', '$PurchaseDate' )
ON DUPLICATE KEY
UPDATE Products.TotalQuantity =
( select sum(Products_Purchased.Quantity) from Products_Purchased
where ProductID = '$ProductID' )
- ( select sum(Products_Sold.Quantity) from Products_Sold
where ProductID = '$ProductID' )
答案 0 :(得分:0)
愿它有所帮助
UPDATE table1,table2 SET table1.column1 = ( SELECT SUM( (SELECT常量FROM table3)+ (SELECT table2.sum_number *** WHERE table2.table2_id1 = table1.id) ) ) WHERE table1.id = table2.table2_id1;
UPDATE table1 SET column1 = (SUM(table2{& table3} WHERE table2_id1 = id1) WHERE id1 = table2_id1
答案 1 :(得分:0)
试试这个
update products t1,
(select productid,sum(Products_Purchased.Quantity) as x from Products_Purchased
group by productid having ProductID = '$ProductID' ) t2,
(select productid,sum(Products_Sold.Quantity) as y from Products_Sold
group by productid having ProductID = '$ProductID' ) t3
set TotalQuantity=t2.x-t3.y where t1.ProductID = '$ProductID'
and t1.productid=t2.productid and t1.productid=t3.productid