Question

我在互联网上搜索过，但我找不到问题的答案也没有运气。我希望这还没有特别发布，但如果你能指出我能找到答案的地方，我将不胜感激。

我能够得到以下表格数据：

id   lead_id form_id field_number   value
1       1      1        1           Hosker
2       1      1        7           b**********@yahoo.com
3       1      1        6           Hyundai Tournament of Champions
4       1      1        3           Adam Scott
5       1      1        4           Harris English
6       1      1        5           2014-01-02 23:59:47
7       1      1        8           5b409692-e9ed-486e-8d77-7d734f1e023d

使用此查询字符串获取下面的结果：

SELECT id, lead_id, form_id, 
MAX(case when field_number = 1 then value end) username, 
MAX(case when field_number = 7 then value end) email, 
MAX(case when field_number = 6 then value end) tournament_name, 
MAX(case when field_number = 3 then value end) primary_golfer, 
MAX(case when field_number = 4 then value end) backup_golfer, 
MAX(case when field_number = 5 then value end) date, 
MAX(case when field_number = 8 then value end) tournament_id 
FROM `wp_rg_lead_detail` GROUP BY lead_id



id   lead_id form_id field_number   value     value                  value                              value          value            value                      value
 1      1      1        1           Hosker    b**********@yahoo.com  Hyundai Tournament of Champions    Adam Scott    Harris English    2014-01-02 23:59:47    5b409692-e9ed-486e-8d77-7d734f1e023d

我只希望该查询字符串仅在tournament_id列的值等于特定值时才提取相关数据。我该怎么做？

Answer 1

如果我理解你的要求，请尝试：

SELECT * FROM TABLE_NAME
WHERE tournament_id = specific_value;

Answer 2

尝试此查询。我想你可以使用HAVING子句。

SELECT id, lead_id, form_id, 
MAX(case when field_number = 1 then value end) username, 
MAX(case when field_number = 7 then value end) email, 
MAX(case when field_number = 6 then value end) tournament_name, 
MAX(case when field_number = 3 then value end) primary_golfer, 
MAX(case when field_number = 4 then value end) backup_golfer, 
MAX(case when field_number = 5 then value end) date, 
MAX(case when field_number = 8 then value end) tournament_id 
FROM `wp_rg_lead_detail` GROUP BY lead_id
HAVING tournament_id = '5b409692-e9ed-486e-8d77-7d734f1e023d'

sqlFiddle在sqlFiddle中我有2个不同的tournament_id的样本数据，并且应用HAVING子句以便只返回该tournament_id的值，你可以尝试删除HAVING并看到它返回2行。

您的Group By不是标准的，因为您也选择了id和form_id。我建议你删除id或使用MIN（id）或MAX（id）和GROUP BY lead_id,form_id

使用Pivot Table mySQL查询特定值

2 个答案: