Question

我有一个查询生成带有累积列（累积）的下表

+--+---+--------+------+
|id|qty|cumulate|value |
+--+---+--------+------+
|1 |5  |5       |419.6 |
+--+---+--------+------+
|2 |2  |7       |167.84|
+--+---+--------+------+
|3 |1  |8       |83.92 |
+--+---+--------+------+
|4 |2  |10      |167.84|
+--+---+--------+------+
|5 |1  |11      |83.92 |
+--+---+--------+------+
|6 |5  |16      |419.6 |
+--+---+--------+------+

但是我需要对查询的进一步附件，它只会选择累计最多9行的所有行。在这种情况下，前4行累计最多10行，前3行累积; 8。

我需要提取qty不多且不小于9的总值的总和。行按日期顺序排列（日期未显示），因此行不能重新排序。

如何实现这一目标？

修改

这是我的查询（但上面的结果表与此查询产生的输出不同）：

select branch, 
    case  
        when DATEDIFF(MONTH, dateInv, getDate()) between 0 and 6 then '0-6' 
        when DATEDIFF(MONTH, dateInv, getDate()) between 7 and 12 then '7-12'   
        when DATEDIFF(MONTH, dateInv, getDate()) between 13 and 18 then '13-18' 
        when DATEDIFF(MONTH, dateInv, getDate()) between 19 and 24 then '19-24'
        when DATEDIFF(MONTH, dateInv, getDate()) between 25 and 36 then '25-36' 
        when DATEDIFF(MONTH, dateInv, getDate()) > 36 then '>36'    
    end [period]
    ,sum(qty*cost) [costs]
from (
    select branch,qty, dateInv, max(cost)cost, max(soh)[qoh], SUM(qty*cost)[sumqty]
        , sum(qty) over (partition by product order by dateInv desc) [cumulate] 
    from openquery(linkedserver,
    'select   branch,product, soh, cost, dateInv, qty
     from table
     group by branch,product, soh, cost, dateInv, qty
     order by dateInv DESC
    ')
    group by branch,product,qty, dateInv
)t
where cumulate <= qoh
group by branch, dateInv

Answer 1

从它的外观来看，每1个数量的值为83.92。 9 * 83.92 = 755.28

Answer 2

感谢大家的尝试。我设法通过使用一系列带有“over（partition by）”，Row_number和计算的嵌套查询来解决这个问题。

很有趣！

累积值减去过量

2 个答案: