我在Xcode中创建了带有3列,2和3列的选择器,根据第一列中的数据填充了数据。它运行正常,数据正确显示,我唯一的问题是如何编写当前显示2和3.列的选定行的值到某个字符串?
谢谢。
答案 0 :(得分:1)
使用 - [UIPickerView selectedRowInComponent:]
确定选择了哪一行,然后在数据数组中的该索引处返回该对象。
- (void)pickerView:(UIPickerView *)pickerView didSelectRow: (NSInteger)row inComponent:(NSInteger)component {
NSInteger selectedRow = [pickerView selectedRowInComponent:0];
NSString *selectedPickerRow=[yourArrayOfElements objectAtIndex:selectedRow];
// Handle the selection
}
答案 1 :(得分:0)
实施didSelectRow
委托
- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component {
NSIndexPath *indexPath = [NSIndexPath indexPathForRow:row inSection:0];
UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:indexPath];
NSString *cellText = [NSString stringWithString: cell.textLabel.text];
NSIndexPath *indexPath1 = [NSIndexPath indexPathForRow:row+1 inSection:0];
UITableViewCell *cell1 = [self.tableView cellForRowAtIndexPath:indexPath1];
NSString *cell1Text = [NSString stringWithString: cell1.textLabel.text];
NSIndexPath *indexPath2 = [NSIndexPath indexPathForRow:row+2 inSection:indexPath.section];
UITableViewCell *cell2 = [self.tableView cellForRowAtIndexPath:indexPath2];
NSString *cell2Text = [NSString stringWithString: cell2.textLabel.text];
}