Question

我有一些Tastypie资源在调用时会呈现类似的内容：

{
   "meta":{
      "limit":1,
      "next":"/api/v1/studio/?limit=1&offset=1",
      "offset":0,
      "previous":null,
      "total_count":93
   },
   "objects":[
      {
         "full_address":"1234 Main St.",
         "resource_uri":"/api/v1/studio/3/",
         "state":{
            "resource_uri":"/api/v1/state/110/",
            "state_id":110,
            "state_name":"Colorado",
            "studios":[
               "/api/v1/studio/3/",
               "/api/v1/studio/4/",
               "/api/v1/studio/5/",
               "/api/v1/studio/6/",
               "/api/v1/studio/8/",
               "/api/v1/studio/11/",
               "/api/v1/studio/12/",
               "/api/v1/studio/13/",
               "/api/v1/studio/14/",
               "/api/v1/studio/15/",
               "/api/v1/studio/1/",
               "/api/v1/studio/2/"
            ]
         }
      }
   ]
}

我可以使用use_in和Tastypie从列表视图中排除相关字段吗？我可以像这样排除直接资源的字段：

exclude_this_field = fields.CharField(use_in='detail', attribute='exclude_this_field')

State是Studio的ForeignKey字段。如何排除相关资源？

studios = fields.Charfield(use_in='detail', attribute='state__state_id')

我可以制作类似这样的工作来排除相关资源吗？

Answer 1

如果要隐藏ForeignKeyField的详细信息或列表覆盖资源的init函数，并在调用对象父init后添加use_in值。它应该是这样的：

class YourResource(ModelResource)
    ...
    class Meta:
        ...
    def __init__(self, *args, **kwargs):
        # Call the object's parent, which will set up and populate
        # the Resource fields from the queryset provided
        super(YourResource, self).__init__(*args, **kwargs)
        # Now loop through the fields of the resource, and when we
        # find the one we only want to be shown in the detail view,
        # set its use_in attr appropriately
        for field_name, field_object in self.fields.items():
            if field_name == 'yourForeignFieldName':
                field_object.use_in = 'detail'

我希望这会有所帮助，欢呼！

Django Tastypie use_in与关系

1 个答案: