有人可以帮我解决如何使用字符串标记器在Java编程中将单词转换为数字的方法。您的回答将受到高度赞赏。
已编辑: 我已经制作了这段代码。但是有一个错误。就像我输入一千一百,程序输出100100。需要你的帮助。您认为我的计划有什么问题,我该怎么办?非常感谢..
import javax.swing.*;
import java.util.*;
import java.text.*;
public class convertwordstonumbers {
public static void main(String[] args) {
String sInput;
sInput=JOptionPane.showInputDialog("Enter a word/s:");
StringTokenizer sToken= new StringTokenizer(sInput);
int Tokens=sToken.countTokens();
String Words[]=new String[Tokens];
double Numbers[]=new double[Tokens];
double Multiplier[]=new double[Tokens];
String Place[]=new String[Tokens];
int a=0;
while(sToken.hasMoreTokens())
{
Words[a]=sToken.nextToken();
a++;
}
String sUnits[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
String sTeens[]= {"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};
String sTys[]={"twenty","thirty","fourty","fifty","sixty","seventy","eighty","ninety"};
String sIons[]={"hundred","thousand","million","billion"};
String sThs[]={"tenths","hundredths"};
double iUnits[]={0,1,2,3,4,5,6,7,8,9};
double iTeens[]={10,11,12,13,14,15,16,17,18,19};
double iTys[]={20,30,40,50,60,70,80,90};
double iIons[]={100,1000,1000000,1000000000};
double iDecs[]={0.1,0.01};
double iSum=0;
for(int b=0;b<Tokens;b++){
for(int c=0;c<10;c++){
if(Words[b].compareToIgnoreCase(sUnits[c])==0){
Numbers[b]=iUnits[c];
Place[b]="a";
}
}
for(int c=0;c<10;c++){
if(Words[b].compareToIgnoreCase(sTeens[c])==0){
Numbers[b]=iTeens[c];
Place[b]="a";
}
}
for(int c=0;c<8;c++){
if(Words[b].compareToIgnoreCase(sTys[c])==0){
Numbers[b]=iTys[c];
Place[b]="a";
}
}
for(int c=0;c<4;c++){
if(Words[b].compareToIgnoreCase(sIons[c])==0){
Numbers[b]=iIons[c];
Place[b]="b";
Multiplier[b]=iIons[c];
}
}
for(int c=0;c<2;c++){
if(Words[b].compareToIgnoreCase(sThs[c])==0){
Numbers[b]=iDecs[c];
Place[b]="b";
}
}
}
for(int d=0;d<Tokens;d++){
if(Place[d]==null){
JOptionPane.showMessageDialog(null, "Invalid input");
System.exit(0);
}
if(Place[d]=="a")
iSum+=Numbers[d];
if(Place[d]=="b")
iSum*=Numbers[d];
}
if (iSum<1000)
{DecimalFormat dFormat= new DecimalFormat("0.00");
System.out.println(dFormat.format(iSum));}
else
{DecimalFormat dFormat= new DecimalFormat("0,000.00");
System.out.println(dFormat.format(iSum));
}
}``
}
答案 0 :(得分:1)
我认为stringtokenizer是不够的,你需要一本字典从你的语言转换为数字
另见 http://nlp.stanford.edu/nlp/javadoc/javanlp/edu/stanford/nlp/ie/NumberNormalizer.html
提供将单词转换为数字的函数与QuantifiableEntityNormalizer不同,它将各种类型的可量化实体(如money和date)规范化,NumberNormalizer仅规范化数值表达式(例如,一个=> 1,200 => 200.0)
答案 1 :(得分:1)
StringTokenizer有一个允许特定分隔符的构造函数。假设您希望用空格“”分隔每个标记,您可以使用ArrayList,每个标记使用数字0-9预先特定放置。
ArrayList<String> token;
token.add("zero");
token.add("one"); ... etc
StringTokenizer s = new StringTokenizer("four zero four", " ");
String num_rep = token.indexOf(s.nextToken()) + token.indexOf(s.nextToken()) + token.indexOf(s.nextToken());
答案 2 :(得分:0)
你需要编写一个逻辑来比较字符串和标准字,然后在旅途中建立数字。
只是观察:StackOverflow不是解决你的作业的地方。