我有这些表格:
pupils: (id_pupil, name, surname, email, user, pass, level, class)
incidents: (id_incidents, date, time, type_incident, comments, id_pupil, id_user, subject, id_trimester)
qualifications: (id_qualification, qualification, date, time, subject, id_pupil, id_user, id_trimester, type_qualification)
我做了这个查询:
SELECT
pupils.id_pupil
, name
, surname
, round(avg(qualifications.calificacion),2) as average
, count(qualifications.calificacion) as count
, COALESCE(sum(type_incident='miss' and level=1 and class='A' and id_trimester=1),0) as misses
, COALESCE(sum(type_incident='delay' and level=1 and class='A' and id_trimester=1),0) as delays
, COALESCE(sum(type_incident='attitude' and level=1 and class='A' and id_trimester=1),0) as attitude
, COALESCE(sum(type_incident='miss_justif' and level=1 and class='A' and id_trimester=1),0) as misses_justificadas
FROM
pupils
left join incidents ON incidents.id_pupil=pupils.id_pupil
left join qualifications ON qualifications.id_pupil=pupils.id_pupil
WHERE
level=1
and class='A'
and id_trimester=1
and type_qualification='class'
and qualifications.id_trimester=incidents.id_trimester
GROUP BY id_pupil
但问题是,我必须得到的正确结果是:
我得到了:
问题在于,增加了班级资格和未命中数(17x6(2个未命中,1个延迟,1个态度和2个misses_just)= 102))并且我不希望这样。我想在第一张图片中显示正确的信息。
你想帮助我吗?
谢谢!
答案 0 :(得分:0)
问题是您正在创建的关系会复制大量行。
我个人的做法是:
incidents
这样的事情:
select
p.id_pupil, p.name, p.surname,
(case
when type_incident = 'miss' and level = 1 and class='A' then incident_count
else 0
end) as misses,
(case
when type_incident = 'delay' and level = 1 and class='A' then incident_count
else 0
end) as delays,
(case
when type_incident = 'attitude' and level = 1 and class='A' then incident_count
else 0
end) as attitude,
(case
when type_incident = 'miss_justif' and level = 1 and class='A' then incident_count
else 0
end) as miss_justif
from
pupils as p
left join (
select id_pupil, class, id_trimester, type_qualification, avg(qualification) as q_avg
from qualifications
group by id_pupil, class, id_trimester, type_qualification
) as q on p.id_pupil = q.id_pupil
left join (
select id_pupil, class, type_incident, level, class, count(id_incidents) as incident_count
from incidents
group by id_pupil, id_trimester, incident, level, class
) as i on p.id_pupil = i.id_pupil
where ...