Question

我的Android应用上有一个忘记密码页面。如果我没有输入电子邮件，它会从服务器返回正确的响应，如果我输入在我们的数据库中找到的电子邮件，那么它会向用户发送电子邮件并从服务器返回正确的响应。但是，如果我输入电子邮件但在我们的数据库中找不到它，那么当我打电话

时

HttpEntity entity = response.getEntity();

entity是一个空值。我不确定为什么它适用于其中两个案例但不适用于第三个案例。

有谁知道为什么会这样？我的代码如下

Android代码：

private void accessURL(String url) {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(url);

    if (url.equalsIgnoreCase(Global.forgotPasswordURL)) {
        InputStream is = null;
        ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
        nameValuePairs.add(new BasicNameValuePair("email", email.getText().toString()));

        try {
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();

            if(entity != null){
                is = entity.getContent();
                String jsonResult = inputStreamToString(is).toString();
                if (jsonResult.equalsIgnoreCase("Please enter your Email")) {
                    new AlertDialog.Builder(this).setTitle("Please Enter Your Email Address")
                            .setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
                                public void onClick(DialogInterface dialog, int which) {
                                    // continue with delete
                                }
                            }).show();
                }else if(jsonResult.equalsIgnoreCase("Email Address Not Found")){
                    new AlertDialog.Builder(this).setTitle("The Email Address You Entered has not Been Found").setMessage("Make sure that you entered your email correctly.")
                    .setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int which) {

                        }
                    }).show();
                }else{
                    new AlertDialog.Builder(this).setTitle("Your Email Has Been Found!").setMessage("Check the email you provied for further instructions on resetting your password.")
                    .setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int which) {

                        }
                    }).show();
                }
            }else{
                Log.d("Null", "null");
            }

        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

PHP代码：

if (isset($_POST["email"]) && !empty($_POST['email'])) {
        $con=mysqli_connect("localhost","***********","******","*******");
        $email = $_POST['email'];
        $query = mysql_query("SELECT * FROM users WHERE email = '$email'");
        $query2 = mysql_query("SELECT * FROM tempusers WHERE email = '$email'");
        $ans = mysql_num_rows($query);
        $ans2 = mysql_num_rows($query2);
        $str = $ans . " " . $ans2;
        if(mysql_num_rows($query) == 0 && mysql_num_rows($query2) == 0){
            sendResponse(205, "Email Address Not Found");
            return false;
        }
        $temp = false;
        if(mysql_num_rows($query2) != 0){
            $temp = true;
            $query1 = mysql_query("SELECT * FROM tempusers WHERE email = '$email'");
            $row = mysql_fetch_array($query1);
            mailUser($email, $row['firstname'], $temp);

            sendResponse(200, "Email Address Found".$str);
            return true;
        }else{
            $query1 = mysql_query("SELECT * FROM users WHERE email = '$email'");
            $row = mysql_fetch_array($query1);
            mailUser($email, $row['firstname'], $temp);

            sendResponse(200, "Email Address Found".$str);
            return true;
        }
    }
    sendResponse(400, 'Please enter your Email');
    return false;

非常感谢任何帮助解决这个问题，谢谢！

Answer 1

据我所知，它的行为符合HttpEntity的规范，适用于205条回复。这是规范所说的：

HTTP消息可以携带与请求关联的内容实体或回应。在某些请求和某些请求中可以找到实体答案，因为它们是可选的。使用实体的请求是称为封闭请求的实体。 HTTP规范定义了两个封闭请求方法的实体：POST和PUT。回应通常期望包含内容实体。 有例外 这个规则，如对HEAD方法的响应和204 No Content，304 未修改， 205重置内容响应。

如果未找到电子邮件，您可以使用PHP发送404响应代码并检入Java代码：

if(response.getStatusLine().getStatusCode() == 404){
  //email was not found
}

Answer 2

为未找到的电子邮件发送相同的200代码

sendResponse(200, "Email Address Not Found");

HTTPEntity给出null值

2 个答案: