Question

我想用“添加”按钮创建一个表单。按“添加”按钮后，新面板将添加到wicket ListView元素中。我怎么做？我希望能够添加无限数量的行。

修改

InteractivePanelPage.html

<table>
    <tr>
        <td><a href="#" wicket:id="addPanelLink">Add Panel</a></td>
    </tr>
    <tr wicket:id="interactiveListView">
        <td>
        <span wicket:id="interactiveItemPanel"></span>
        </td>
    </tr>
</table>

InteractivePanelPage.java

// ... imports
public class InteractivePanelPage extends WebPage {
    public LinkedList<InteractivePanel> interactivePanels = new LinkedList<InteractivePanel>();

    private ListView<InteractivePanel> interactiveList;

    public InteractivePanelPage() {
        add(new AjaxLink<String>("addPanelLink") {
            private static final long serialVersionUID = 1L;

            @Override
            public void onClick(AjaxRequestTarget target) {
                try {
                    System.out.println("link clicked");

                    InteractivePanel newInteractivePanel = new InteractivePanel(
                            "interactiveItemPanel");
                    newInteractivePanel.setOutputMarkupId(true);

                    interactiveList.getModelObject().add(newInteractivePanel);
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        });

        interactivePanels.add(new InteractivePanel("interactiveItemPanel"));

        interactiveList = new ListView<InteractivePanel>("interactiveListView",
                new PropertyModel<List<InteractivePanel>>(this, "interactivePanels")) {
            private static final long serialVersionUID = 1L;

            @Override
            protected void populateItem(ListItem<InteractivePanel> item) {
                item.add(item.getModelObject());
            }
        };

        interactiveList.setOutputMarkupId(true);

        add(interactiveList);
    }

    public List<InteractivePanel> getInteractivePanels() {
        return interactivePanels;
    }
}

InteractivePanel.html

<html xmlns:wicket>
<wicket:panel>
<span><input type="button" value="BLAAA" wicket:id="simpleButton"/></span>
</wicket:panel>
</html>

InteractivePanel.java

// ... imports
public class InteractivePanel extends Panel {
    private static final long serialVersionUID = 1L;

    public InteractivePanel(String id) {
        super(id);

        add(new Button("simpleButton"));
    }
}

这根本行不通。谁能明白为什么？感谢

Answer 1

我想你已经在ListView中显示了一个元素列表？您只需将新元素添加到备份ListView的列表中即可。如果您在构造函数中传入List，则认为ListView不会刷新项目。

所以，而不是

List<Person> personList = new LinkedList<Person>();
ListView<Person> personView = new ListView<Person("listview", personList);

你应该使用一个包装List的模型：

ListView<Person> personView = new ListView<Person("listview"
               , new PropertyModel<List<Person>>(this, "personList");

以及此中的getPersonList（）访问器。

您可以查看Legup并生成Wicket，Spring，JPA原型。在代码中，您将找到执行此操作的EventPage。

将组件动态添加到Wicket中的ListView

1 个答案: