我正在尝试从Paperjs(http://paperjs.org/examples/meta-balls/)自定义元球示例。问题是,即使是复制粘贴它也不会起作用。它不会绘制/显示球之间的“桥梁”。
这是一个jsFiddle:http://jsfiddle.net/AK47p/
这是代码:
$(document).ready(function () {
// Get a reference to the canvas object
var canvas = document.getElementById('canvas');
// Create an empty project and a view for the canvas:
paper.setup(canvas);
// Create a simple drawing tool:
var tool = new paper.Tool();
// Ported from original Metaball script by SATO Hiroyuki
// http://park12.wakwak.com/~shp/lc/et/en_aics_script.html
paper.project.currentStyle = {
fillColor: 'black'
};
var ballPositions = [[255, 129], [610, 73], [486, 163],
[117, 259], [484, 326], [843, 306], [789, 215], [949, 82],
[292, 128], [917, 233], [352, 86], [92, 98]];
var handle_len_rate = 2.4;
var circlePaths = [];
var radius = 50;
for (var i = 0, l = ballPositions.length; i < l; i++) {
var circlePath = new paper.Path.Circle({
center: ballPositions[i],
radius: 50
});
circlePaths.push(circlePath);
}
var largeCircle = new paper.Path.Circle({
center: paper.view.center,
radius: 100,
fillColor: 'green'
});
circlePaths.push(largeCircle);
tool.onMouseMove = function(event) {
largeCircle.position = event.point;
generateConnections(circlePaths);
}
var connections = new paper.Group(); var thePath;
function generateConnections(paths) {
// Remove the last connection paths:
connections.children = [];
for (var i = 0, l = paths.length; i < l; i++) {
for (var j = i - 1; j >= 0; j--) {
var path = metaball(paths[i], paths[j], 0.5, handle_len_rate, 300);thePath = path;
if (path) {
connections.appendTop(path);
path.removeOnMove();
}
}
}
}
generateConnections(circlePaths);
// ---------------------------------------------
function metaball(ball1, ball2, v, handle_len_rate, maxDistance) {
var center1 = ball1.position;
var center2 = ball2.position;
var radius1 = ball1.bounds.width / 2;
var radius2 = ball2.bounds.width / 2;
var pi2 = Math.PI / 2;
var d = center1.getDistance(center2);
var u1, u2;
if (radius1 == 0 || radius2 == 0)
return;
if (d > maxDistance || d <= Math.abs(radius1 - radius2)) {
return;
} else if (d < radius1 + radius2) { // case circles are overlapping
u1 = Math.acos((radius1 * radius1 + d * d - radius2 * radius2) /
(2 * radius1 * d));
u2 = Math.acos((radius2 * radius2 + d * d - radius1 * radius1) /
(2 * radius2 * d));
} else {
u1 = 0;
u2 = 0;
}
var angle1 = center2.subtract(center1).getAngleInRadians();
var angle2 = Math.acos((radius1 - radius2) / d);
var angle1a = angle1 + u1 + (angle2 - u1) * v;
var angle1b = angle1 - u1 - (angle2 - u1) * v;
var angle2a = angle1 + Math.PI - u2 - (Math.PI - u2 - angle2) * v;
var angle2b = angle1 - Math.PI + u2 + (Math.PI - u2 - angle2) * v;
var p1a = center1 + getVector(angle1a, radius1);
var p1b = center1 + getVector(angle1b, radius1);
var p2a = center2 + getVector(angle2a, radius2);
var p2b = center2 + getVector(angle2b, radius2);
// define handle length by the distance between
// both ends of the curve to draw
var totalRadius = (radius1 + radius2);
var d2 = Math.min(v * handle_len_rate, (p1a - p2a).length / totalRadius);
// case circles are overlapping:
d2 *= Math.min(1, d * 2 / (radius1 + radius2));
radius1 *= d2;
radius2 *= d2;
var path = new paper.Path({
segments: [p1a, p2a, p2b, p1b],
style: ball1.style,
closed: true
});
var segments = path.segments;
segments[0].handleOut = getVector(angle1a - pi2, radius1);
segments[1].handleIn = getVector(angle2a + pi2, radius2);
segments[2].handleOut = getVector(angle2b - pi2, radius2);
segments[3].handleIn = getVector(angle1b + pi2, radius1);
return path;
}
// ------------------------------------------------
function getVector(radians, length) {
return new paper.Point({
// Convert radians to degrees:
angle: radians * 180 / Math.PI,
length: length
});
}
});
正如您所看到的,我将代码包装在domReady函数中,因为它将成为幻灯片演示的一部分。我按照这里的说明(http://paperjs.org/tutorials/getting-started/using-javascript-directly/)来做到这一点。知道什么是错的吗?我一遍又一遍地检查,我一定错过了什么......
谢谢
答案 0 :(得分:1)
找出遗漏的东西。 Paperjs上没有很好的文档,无论如何,如果你像普通的javascript一样使用它,确保纸对象(Point,Path等)上的所有操作都表示为方法,而不是作为运算符。
<强>错强>
var d2 = Math.min(v * handle_len_rate, (point1a - point2a).length / totalRadius);
从右强>
var d2 = Math.min(v * handle_len_rate, point1a.subtract(point2a).length / totalRadius);