Question

点击退出按钮时，我想在购物车中取消设置用户名。如果我想放，如果点击退出，那么会话将取消设置，我应该怎么做？

我的代码有效但是，当我再次点击登录时，登录信息不存储在会话中。它一直要求我再次登录，而不是继续通常的流程。我可以知道出了什么问题吗？

这是我的代码 cart.php

$logout = "allproducts.php";

if(isset($logout))
{
    unset($_SESSION['supermarketcart']);
    unset($_SESSION['MM_Username']);
}

?>

<?php 

          if(isset($_SESSION['MM_Username']) == NULL) 
          { 
              echo "<a href='login.php'>Login</a> " ;

          } 
          else 
          { 
              echo " <a href='$logout'>Logout</a> "; 
          }
      ?>

的login.php

<?php
// *** Validate request to login to this site.
if (!isset($_SESSION)) {
  session_start();
}

$loginFormAction = $_SERVER['PHP_SELF'];
if (isset($_GET['accesscheck'])) {
  $_SESSION['PrevUrl'] = $_GET['accesscheck'];
}

if (isset($_POST['username'])) {
  $loginUsername=$_POST['username'];
  $password=$_POST['password'];
  $MM_fldUserAuthorization = "";
  $MM_redirectLoginSuccess = "index.php";
  $MM_redirectLoginFailed = "login.php?fail=1";
  $MM_redirecttoReferrer = false;
  mysql_select_db($database_MyDatabase, $MyDatabase);

  $LoginRS__query=sprintf("SELECT username, password FROM user_data WHERE username=%s AND password=%s",
    GetSQLValueString($loginUsername, "text"), GetSQLValueString($password, "text")); 

  $LoginRS = mysql_query($LoginRS__query, $MyDatabase) or die(mysql_error());
  $loginFoundUser = mysql_num_rows($LoginRS);
  if ($loginFoundUser) {
     $loginStrGroup = "";

    if (PHP_VERSION >= 5.1) {session_regenerate_id(true);} else {session_regenerate_id();}
    //declare two session variables and assign them
    $_SESSION['MM_Username'] = $loginUsername;
    $_SESSION['MM_UserGroup'] = $loginStrGroup;       

    if (isset($_SESSION['PrevUrl']) && false) {
      $MM_redirectLoginSuccess = $_SESSION['PrevUrl'];  
    }
    header("Location: " . $MM_redirectLoginSuccess );
  }
  else {
    header("Location: ". $MM_redirectLoginFailed );
  }
}
?>

Answer 1

正如Barmar所说的，你总是拥有一个始终如一的状态，总是会让你的部分无法解决。你应该做什么，是一个静态地址登出页面与GET变量通过。我们将其设为$_GET['logout']并指定值1

   <?php 
      if(isset($_SESSION['MM_Username']) == NULL) 
      { 
          echo "<a href='login.php'>Login</a> " ;

      } 
      else 
      { 
          echo " <a href='allproducts.php?logout=1'>Logout</a> "; 
      }
  ?>

然后检查GET variable而不是始终存在的$logout

if($_GET['logout']==1)
{
    unset($_SESSION['supermarketcart']);
    unset($_SESSION['MM_Username']);
}

unset session不能很好地运行PHP

1 个答案: